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Line-integral estimates by arc length and the supremum of the field
Statement
Let be a piecewise- path of length , let be a continuous scalar field and a continuous vector field on its trace, and let .
- If on the trace of , then
- If on the trace of , then
Facts & Assumptions
Given: The path, fields, and bound in the Statement.
Line integrals are sums over smooth pieces of or (Scalar line integrals with respect to arc length and vector-field line integrals).
The Euclidean Cauchy-Schwarz inequality is (Cauchy-Schwarz with its equality case, the triangle inequality for , the parallelogram law and polarisation).
The Riemann integral is linear, and pointwise order between integrable functions is preserved by integration (Integrable functions on form a set closed under sums and scalar multiples, and , If on and both are integrable then ; and ).
For an admissible partition, is the sum of the integrals of the speeds (A continuous piecewise- path is rectifiable and its length is the sum of the speed integrals over its pieces).
Proof
On each smooth piece,
By [L2] and the bound on ,
Integrate the two inequalities in step 1.1 using [L3], sum them using [L1], and identify the speed sum with [L4]. This gives hence the scalar estimate.
Repeating step 2.1 with step 1.2 gives the vector estimate.
If or , either two-sided bound has both endpoints equal to zero, so the corresponding integral is zero and the asserted estimate still holds.
Depends on
- Scalar line integrals with respect to arc length and vector-field line integrals
- Cauchy-Schwarz $\lvert\langle x,y\rangle\rvert \le \lVert x\rVert_2\lVert y\rVert_2$ with its equality case, the triangle inequality for $\lVert\cdot\rVert_2$, the parallelogram law and polarisation
- If $f \le g$ on $[a,b]$ and both are integrable then $\int_a^b f \le \int_a^b g$; and $m(b-a) \le \int_a^b f \le M(b-a)$
- Integrable functions on $[a,b]$ form a set closed under sums and scalar multiples, and $\int_a^b(\lambda f+\mu g) = \lambda\int_a^b f + \mu\int_a^b g$
- A continuous piecewise-$C^1$ path is rectifiable and its length is the sum of the speed integrals over its pieces
Used by
Nothing in the library uses this result yet.
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Sources
- J. Lebl, Basic Analysis II, Proposition 9.2.10 (standard reference, not scraped)