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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
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Schur's theorem: every finite colouring of a sufficiently long positive initial interval {1,…,N} has positive monochromatic x,y,z with x+y=z

Statement

For every positive number c of colours there is a positive natural N such that every c-colouring of {1,…,N} has positive x,y,z of one colour satisfying x+y=z. The variables need not be distinct. Natural order is that of The natural numbers N (von Neumann) and Order on the natural numbers, and the proof uses the pair-colouring convention of Finite colourings of k-element subsets, monochromatic sets, and the arrow notations N→(s,t)2 and N→(r)ck.

Facts & Assumptions

Given: A positive number c of colours and a colouring of a sufficiently long positive initial interval.

[L1]

For all positive s,t, (s+t−2s−1)→(s,t)2 (Finite graph Ramsey theorem: (s+t−2s−1)→(s,t)2 for all positive s,t).

Proof

technique · direct
1.1

Iterating [L1] gives a finite M such that every c-colouring of the pairs of an M-element set has a monochromatic triangle: separate one colour from the remaining colours, use [L1] with target 3 for the first colour and with a recursively chosen target for the others, and continue through the finite colour list.

L1
2.1

Colour the edge {i,j} of the ordered vertex set {0,…,M−1}, with i<j, by the given colour of the positive difference j−i. Step 1.1 gives a monochromatic triangle i<j<k.

step 1.1
3.1

Put x=j−i, y=k−j and z=k−i. These are positive, the edge colouring says they have one original colour, and arithmetic gives x+y=z. Taking N=M−1 contains all three differences.

step 2.1algebra∎

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Sources