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If is not an eigenvalue and one simple eigenvalue is uniquely nearest to , shifted inverse iteration converges to its eigendirection
Statement
Let be diagonalisable with eigenpairs , let , and suppose one simple eigenvalue satisfies
If the start vector has nonzero -component, then shifted inverse iteration with shift converges projectively to the eigendirection of .
Facts & Assumptions
Given: A diagonalisable matrix , a shift not equal to any eigenvalue, and a start vector with nonzero -component.
Shifted inverse iteration is power iteration for (Inverse iteration and shifted inverse iteration).
Power iteration converges projectively under a simple strictly dominant eigenvalue and a nonzero component in its eigendirection (If a diagonalisable matrix has a simple eigenvalue of strictly largest modulus and the start vector has a nonzero component in that eigendirection, power iteration converges projectively at the eigenvalue-ratio rate).
Proof
The eigenvectors of are the same , and the corresponding eigenvalues are . The hypothesis means
Therefore has a simple eigenvalue of strictly largest modulus in the eigendirection . The start vector has nonzero -component by hypothesis, so [L2] applies.
Since [L1] identifies shifted inverse iteration with that power iteration, the iterates converge projectively to the eigendirection of .
Depends on
Used by
Dependency tree · two levels
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Sources
- Andrew Stuart and Jochen Voss, Matrix Analysis and Algorithms (standard reference, not scraped)