Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
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Smooth invariance of the manifold boundary

Statement

A smooth diffeomorphism between relatively open half-space sets carries face points to face points and relative-interior points to relative-interior points; consequently ∂M and Int⁡M are intrinsic.

Facts & Assumptions

Given: Relatively open sets U,V⊆Hn and a smooth diffeomorphism f:U→V.

[L1]

In dimension zero the model face is empty and every point of H0 is a relative-interior point (Interior and boundary of a manifold with boundary).

[L2]

Smooth half-space maps satisfy the intrinsic chain-rule formula (Chain rule for smooth half-space maps).

Proof

technique · direct
1.1givenL1L2cases

If n=0, [L1] makes the claim immediate. Assume n≥1. At any p∈U, choose Euclidean extensions of f and f−1 near p and f(p). Since both half-space composites are the identity, [L2] gives D(f−1)f(p)Dfp=I and DfpD(f−1)f(p)=I.

2.1givenstep 1.1algebra∎

For n≥1, if a face point p mapped to the relative interior, then on a Euclidean neighbourhood of f(p) contained in V, the last coordinate of an extension of f−1 would be nonnegative and would vanish at the interior point f(p). Its differential there would therefore be zero, contradicting the invertibility from step 1.1. Applying the same argument to f−1 proves the converse. Hence face and relative-interior points are preserved in every dimension, making the manifold boundary and interior intrinsic.

Depends on

Used by

Dependency tree · two levels

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Sources