Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
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Smooth invariance of the manifold boundary

Statement

A smooth diffeomorphism between relatively open half-space sets carries face points to face points and relative-interior points to relative-interior points; consequently M and IntM are intrinsic.

Facts & Assumptions

Given: Relatively open sets U,VHn and a smooth diffeomorphism f:UV.

[L1]

In dimension zero the model face is empty and every point of H0 is a relative-interior point (Interior and boundary of a manifold with boundary).

[L2]

Smooth half-space maps satisfy the intrinsic chain-rule formula (Chain rule for smooth half-space maps).

Proof

technique · direct
1.1

If n=0, [L1] makes the claim immediate. Assume n1. At any pU, choose Euclidean extensions of f and f1 near p and f(p). Since both half-space composites are the identity, [L2] gives D(f1)f(p)Dfp=I and DfpD(f1)f(p)=I.

givenL1L2cases
2.1

For n1, if a face point p mapped to the relative interior, then on a Euclidean neighbourhood of f(p) contained in V, the last coordinate of an extension of f1 would be nonnegative and would vanish at the interior point f(p). Its differential there would therefore be zero, contradicting the invertibility from step 1.1. Applying the same argument to f1 proves the converse. Hence face and relative-interior points are preserved in every dimension, making the manifold boundary and interior intrinsic.

givenstep 1.1algebra

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