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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
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The interior is an open smooth n-manifold

Statement

For an n-manifold with boundary, IntM is open and, with restricted charts, is a smooth boundaryless n-manifold.

Facts & Assumptions

Given: A smooth n-manifold M with boundary.

[L1]

For n>0, interior points have positive last boundary-chart coordinate; for n=0, every point is interior, and these classifications are intrinsic (Interior and boundary of a manifold with boundary; Smooth invariance of the manifold boundary).

[L2]

Boundary-chart images are relatively open in Hn, and their transition maps are smooth (Smooth charts, atlases, and structures with boundary).

Proof

technique · direct
1.1

If n=0, [L1] gives IntM=M; it is open, and its original charts have image in R0, so the conclusion follows. Assume n1. Restrict each boundary chart to the inverse image of {xn>0}. These sets are open and, by [L1], cover exactly IntM.

givenL1algebra
2.1

In the n1 case, their images are Euclidean-open, and [L2] shows that the old transition maps restrict to ordinary smooth transitions. The restricted charts therefore make IntM a smooth boundaryless n-manifold; step 1.1 already handled n=0.

givenL2step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources