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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Specializing forcing kills a Suslin tree

Statement

Let M be a transitive model of ZFC, let T∈M be a Suslin tree in M, and let P(T) be its finite-specialization forcing. Then P(T) is ccc and preserves every cardinal and cofinality of M, in particular ω1M. Moreover, with the internal forcing relation of M,

1P(T)⊩M“the ground tree Tˇ is special and is not Suslin.”

More precisely, P(T) forces that the canonical generic union is a total map Tˇ→ωˇ separating comparable nodes; consequently T remains Aronszajn but acquires an uncountable antichain. This is an internal forcing assertion and does not assert the existence of a generic over the universe.

Facts & Assumptions

Given: M,T and P=P(T) as in the Statement. Assume AC in M.

[F1]

A Suslin tree has height ω1, countable levels, no cofinal branch, and no uncountable antichain; a natural-valued map separating comparable nodes specializes a tree. Aronszajn, Suslin and special trees

[F2]

Conditions in P(T) are finite specializing functions, stronger conditions extend weaker graphs, the empty function is the greatest condition, and compatible conditions have a specializing union. Finite specializing conditions

[F3]

In ZFC the finite-specialization forcing of an Aronszajn tree is ccc. Finite specialization of an Aronszajn tree is ccc

[F4]

Each node-domain set Dt is dense, and the union of a nonempty directed family meeting all Dt is a total specializing function. Dense domains and directed unions of specializing conditions

[F5]

Ccc forcing preserves all ground-model cofinalities and cardinals. Chain conditions preserve high cofinalities and ccc preserves cardinals

[F7]

Under countable choice, a countable union of countable sets is countable. Countable unions of at most countable sets, assuming ACω

[F8]

Check names evaluate to their ground values; name valuation selects exactly the subnames whose coefficients lie in the filter. Valuation of names and M[G], Check-name evaluation and reconstruction of G

[F9]

Forcing is persistent and closed under dense truth, and the forcing theorem relates the internal predicate to truth in generic extensions without asserting that such a generic over the universe exists. Monotonicity, density, and decision for forcing, Forcing theorem

[F10]

A generic extension of a transitive ZFC ground is again a transitive ZFC model. Generic extensions satisfy ZF and preserve ground-model Choice

[A1]

The ground model satisfies AC; its use in the ccc and preservation suppliers and its preservation to the extension are declared explicitly. The Axiom of Choice

Proof

technique · direct forcing and generic-union analysis
1.1F1F2F3F5A1

Since a Suslin tree is Aronszajn, [F3] makes P ccc; [F2] also verifies that P is nonempty with greatest condition 1P=∅. Therefore [F5] says that forcing with P preserves every ground cardinal and cofinality, including ω1M.

1.2F2F4F8

In M form the name f˙={⟨zˇ,p⟩:p∈P and z∈p}. For every nonempty G⊆P, [F8] computes f˙G=⋃G. If G is M-generic, it is a nonempty directed forcing filter and meets every Dt∈M; [F4] therefore makes f=f˙G a total specializing map T→ω. Functionality is not merely inferred from notation: if p,q∈G contain values for the same node, directedness gives r∈G extending both graphs, so [F2] forces those values equal; the identical common-extension argument gives unequal values for every comparable distinct pair.

2.1step 1.1step 1.2F1F5F6F10

Work in such an extension M[G], which satisfies ZFC by [F10]. By step 1.1, ordinals and ω1M are preserved; the old tree set and relation are unchanged, its old countable-level enumerations remain, and its node-height set remains cofinal in ω1M, so T still has height ω1. A branch b admits an injection into ω by f↾b, since comparable distinct nodes have different values. If b were cofinal, its node-height image would be an at most countable cofinal subset of ω1, contradicting [F6]; hence T remains Aronszajn.

3.1step 1.2step 2.1F1F6F7F10

The fibers An=f−1({n}) are antichains and T=⋃n∈ωAn. If every An were countable, [F7] would make T countable; then its cofinal node-height image would again be a countable cofinal subset of ω1 by [F6], impossible. Thus some An is an uncountable antichain. Consequently T is special, remains Aronszajn, and is not Suslin in M[G]. This includes n=0 and does not assume in advance that any fiber is nonempty.

4.1step 1.1step 1.2step 2.1step 3.1F8F9F10A1∎

The preceding conclusions are forced internally. Concretely, below every p∈P, each Dt∩P↓p is dense; a member carrying (t,n) has the corresponding check-pair as a coefficient of f˙, while common refinements give exactly the functionality and specialization calculations of step 1.2. Dense truth and persistence in [F9] therefore force the total-specialization clauses below every condition. The ccc preservation theorem and the ZFC argument of steps 2.1-3.1 then force preservation and non-Suslinity. Hence 1P forces the assertion in the Statement. This uses internal names and forcing only; no M-generic over the universe was postulated.

Remarks

  • “Kills” means destroys the Suslin property, not the tree or its height. The specializing map itself rules out a new cofinal branch, so the forced tree is still Aronszajn.
  • Preservation of ω1 alone does not exhibit an uncountable fiber. The proof also uses ZFC in the extension to make a countable union of countable fibers countable and then uses the cofinal node-height set.

Depends on

Used by

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Sources