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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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The complete bipartite graph Km,n has adjacency spectrum {mn,0m+n2,mn}

Statement

For integers m,n1, the complete bipartite graph Km,n has adjacency spectrum

{mn,0m+n2,mn}.

Facts & Assumptions

Given: Integers m,n1 and the complete bipartite graph Km,n with its two parts of sizes m and n.

[F1]

In Km,n every edge joins the two parts, and every such cross pair is an edge (Empty and complete graphs, complete bipartite graphs, and the convention that Pn and Cn have n vertices).

[F2]

The adjacency spectrum is the multiset of adjacency eigenvalues (Adjacency spectrum, spectral radius, and cospectral graphs).

Proof

technique · direct
1.1

In the vertex order with the first part before the second, the adjacency matrix is A=(0Jm×nJn×m0) by [F1]. If a vector (x,y) has the coordinates of x summing to 0, then Jn×mx=0 and A(x,0)=0. Likewise, if the coordinates of y sum to 0, then A(0,y)=0. These give an (m1)+(n1)=m+n2 dimensional eigenspace for the eigenvalue 0.

F1algebra
2.1

On the remaining two-dimensional subspace of vectors constant on each part, A acts by A(a1m,b1n)=(nb1m,ma1n). Relative to the basis (1m,0) and (0,1n), this action has matrix (0nm0), whose eigenvalues are ±mn. Together with step 1.1 this accounts for all m+n eigenvalues.

step 1.1algebra
3.1

Therefore the adjacency spectrum is exactly {mn,0m+n2,mn} by [F2].

step 1.1step 2.1F2

Depends on

Used by

Dependency tree · two levels

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