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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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The complete graph Kn has adjacency spectrum {n1,(1)n1}

Statement

For every integer n1, the complete graph Kn has adjacency spectrum

{n1,(1)n1},

that is, the eigenvalue n1 once and the eigenvalue 1 with multiplicity n1.

Facts & Assumptions

Given: An integer n1 and the complete graph Kn.

[F2]

The adjacency spectrum is the multiset of eigenvalues of the adjacency matrix (Adjacency spectrum, spectral radius, and cospectral graphs).

Proof

technique · direct
1.1

In the standard vertex order, the adjacency matrix of Kn is JI, where J is the all-ones matrix, because [F1] makes every off-diagonal entry equal to 1 and every diagonal entry equal to 0. The all-ones vector 1 satisfies J1=n1, so (JI)1=(n1)1.

F1algebra
2.1

If x is orthogonal to 1, then the coordinates of x sum to 0, so Jx=0. Hence (JI)x=x. The subspace 1 has dimension n1, so 1 is an eigenvalue with multiplicity at least n1; together with step 1.1 this accounts for all n dimensions.

step 1.1algebra
3.1

Therefore the eigenvalues of the adjacency matrix are exactly n1 and 1 with the stated multiplicities, which is the spectrum by [F2].

step 1.1step 2.1F2

Depends on

Used by

Dependency tree · two levels

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