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Strong separation of a closed and a compact convex set
Statement
Assume the Axiom of Choice. Let be disjoint nonempty convex sets, where is closed and is compact. Then they are strongly separated by a nonzero functional in .
Facts & Assumptions
Given: The Axiom of Choice and disjoint nonempty convex , with closed and compact.
Distance to a fixed nonempty set is continuous (indeed -Lipschitz) (, so the distance to a fixed nonempty set is -Lipschitz).
A continuous real-valued function on a compact metric space attains its minimum (A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value).
Disjoint convex sets, one open, are strictly separated by a nonzero continuous functional (Separation of disjoint convex sets when one is open).
The Axiom of Choice supplies the Hahn–Banach premise in [F3].
Proof
By [F1]--[F2], has a minimum on . It is positive: a zero minimum would put some in the closed set . Choose .
The thickening is open and convex and is disjoint from . Under [A1], apply [F3] to to obtain nonzero with for .
For , take the supremum over in the inequalities from step 2.1. Since , this gives for every . Hence , a positive gap.
Depends on
- Separation of disjoint convex sets when one is open
- Weak, strict, and strong separation
- $|d(x,A) - d(y,A)| \le d(x,y)$, so the distance to a fixed nonempty set is $1$-Lipschitz
- A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value
- Open cover, subcover, compact metric space, and compact subset of a metric space
- The Axiom of Choice
Used by
Dependency tree · two levels
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Sources
- Gerald Teschl, Topics in Real and Functional Analysis, Corollary 5.4 (standard reference, not scraped)