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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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A symmetric second-order principal part has a coordinate-invariant signature normal form

Statement

Fix a point x0 of a scalar second-order operator whose principal part is

i,j=1naij(x0)xixj,aij(x0)=aji(x0).

Then there is a linear change of coordinates near x0 in which the frozen principal quadratic form becomes

ξ12++ξp2ξp+12ξp+q2,

with the remaining r=npq directions absent. The triple (p,q,r) depends only on the quadratic form, not on the chosen coordinates.

Facts & Assumptions

Given: The symmetric coefficient matrix A=(aij(x0))1i,jn of the frozen principal part at x0.

[L1]

The order-2 principal symbol is the quadratic polynomial associated to the symmetric coefficient matrix (Elliptic, hyperbolic, and parabolic principal symbols).

[L2]

A self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis (Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis).

[L3]

A real symmetric bilinear form is congruent to exactly one diagonal form diag(Ip,Iq,0r) (Sylvester's law of inertia: every real symmetric form is congruent to diag(Ip,Iq,0r), and (p,q,r) is unique).

Proof

technique · direct
1.1

By [L1], the frozen principal symbol is p2(ξ)=ξTAξ, and because A is symmetric, [L2] gives an orthonormal eigenbasis in which A is diagonal with real eigenvalues λ1,,λn.

L1L2
2.1

Rescaling each coordinate with λi0 by λi1/2 changes the nonzero diagonal entries to 1 or 1 and leaves the zero eigenvalues unchanged, so the principal form becomes diag(Ip,Iq,0r); by [L3], the numbers of positive, negative, and zero directions are intrinsic.

L3step 1.1
3.1

Therefore the frozen symmetric principal part has the stated signature normal form, and its signature triple is invariant under further invertible linear coordinate changes.

step 2.1

Depends on

Used by

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Sources