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The cohomology universal-coefficient sequence splits nonnaturally
Statement
Assume the Axiom of Choice. Let be a PID, a chain complex of free -modules, an -module, and . The cohomological UCT sequence splits after choosing a complement of in . No splitting natural in the complex is asserted.
Proof
Given: as stated and the UCT sequence of The universal coefficient theorem for cohomology over a PID.
The exact sequence comes from The cycle-boundary short exact sequences for a free complex over a PID. Under AC, Boundaries and cycles in a free complex over a PID are free makes free and Free modules are projective, with the exact choice boundary makes it projective. Lift its identity through to choose a section . Then factors through the inclusion as a projection restricting to the identity on cycles.
Write for the quotient. For , define . The map is a cocycle: lands in , where is the identity and is zero. This assignment is -linear in , so it defines a homomorphism into cohomology.
For a cycle , , so . Thus is a section of the surjection in the exact UCT sequence. Its construction uses the chosen projection; it supplies existence without asserting naturality in .
Depends on
Used by
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Weibel, An Introduction to Homological Algebra (standard reference, not scraped)