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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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The divergence of the curl of a C2 field vanishes

Statement

Let UR3 be open and let F:UR3 be C2. Then curlF is a C1 field on U and

div(curlF)=0on U.

Facts & Assumptions

Given: The open set UR3 and the C2 field F:UR3 of the Statement, with the three coordinates named x,y,z.

[F1]

The divergence of a C1 field G on an open URn is divG=i<niGi (Divergence and curl of a C1 vector field).

[F2]

The curl of a C1 field F on an open UR3 is curlF=(yFzzFy, zFxxFz, xFyyFx) (Divergence and curl of a C1 vector field).

[F3]

A scalar f is of class Ck on U when, for every word (i1,,ir) of coordinate indices with 0rk, the iterated derivative iri1f exists and is continuous on U (Ck maps and multi-index derivative notation in Euclidean space).

[F4]

A map f:URq is of class Ck when each component is of class Ck (Ck Euclidean maps and diffeomorphisms).

[L1]

If f is C2 on an open subset of Rm, then ijf=jif for every pair of coordinate indices (Clairaut--Schwarz theorem for continuous second partial derivatives).

Proof

technique · direct
1.1

By [F2] each coordinate of curlF is a difference of two first partial derivatives of components of F. Since F is C2, [F4] and [F3] with k=2 give that every iterated derivative ijFa exists and is continuous on U, so each coordinate of curlF has continuous first partial derivatives; by [F4] again, curlF is C1 on U and its divergence is defined.

givenF2F3F4
2.1

By [F1] and [F2], div(curlF)=x(yFzzFy)+y(zFxxFz)+z(xFyyFx), which written out is the sum of the six terms xyFz, xzFy, yzFx, yxFz, zxFy and zyFx.

step 1.1F1F2algebra
3.1

Each component of F is C2, so [L1] gives xyFz=yxFz, yzFx=zyFx and zxFy=xzFy. Pairing the six terms of step 2.1 accordingly, xyFz cancels yxFz, yzFx cancels zyFx, and zxFy cancels xzFy.

step 2.1L1
4.1

The six terms therefore sum to zero at every point of U, so div(curlF)=0 on U. The hypothesis that F is C2 is used in step 1.1, so that curlF is C1 and has a divergence, and in step 3.1 as the hypothesis of [L1].

step 3.1

Remarks

  • Where the hypothesis bites. If F is only C1, then curlF is merely continuous and its partial derivatives need not exist, so div(curlF) is not defined; there is nothing to assert, rather than a weaker assertion.

  • The converse. A divergence-free C1 field on a star-shaped open subset of R3 is the curl of something: that is A divergence-free C1 field on a star-shaped open subset of R3 has a vector potential.

Depends on

Used by

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Sources