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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The exterior derivative commutes with pullback

Statement

For every smooth map F:M→N and every form ω on N, d(F∗ω)=F∗(dω).

Facts & Assumptions

Given: The manifolds, forms, vector fields, maps, and coordinates explicitly named in the statement.

[F1]

The preceding result states that On a chart, if ω=∑IωI dxI, then dω=∑IdωI∧dxI. (The local coordinate formula for the exterior derivative).

Proof

technique · direct
1.1given

Fix p∈M, choose target coordinates (y1,…,yn) near F(p), and write ω=∑IωI dyI there. Pullback sends ωI to ωI∘F and dya to d(ya∘F).

2.1F1step 1.1∎

On a neighbourhood of p, the coordinate formula and the pullback wedge law give d(F∗ω)=∑Id(ωI∘F)∧d(yi1∘F)∧⋯∧d(yik∘F)=F∗ ⁣(∑IdωI∧dyI)=F∗(dω). Since p was arbitrary, the identity holds on M.

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources