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PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
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Pullback of forms is smooth functorial and preserves wedges

Statement

For a smooth map F:M→N, pullback sends smooth differential forms on N to smooth differential forms on M, is functorial, and satisfies

F∗(α∧β)=F∗α∧F∗β.

Facts & Assumptions

Given: A smooth map F:M→N, a smooth map G:N→P, and forms α,β on the target.

[F1]

A form pullback is the covariant tensor pullback restricted to alternating tensors (The pullback of a differential form).

[L1]

Covariant tensor pullback is smooth and functorial (Pullback of covariant tensors is smooth and functorial).

[L2]

Fibrewise linear pullback respects tensor products and permutations, hence wedge products (Linear pullback respects tensor products and permutations).

Proof

technique · direct
1.1F1L1given

By [F1], F∗α is obtained from the covariant tensor pullback. Because [L1] sends smooth covariant tensors to smooth covariant tensors and preserves composition, the same is true for forms.

1.2F1L2givenalgebra

At each point p∈M, [F1] and [L2] give (F∗(α∧β))p=dFp∗(αF(p)∧βF(p))=dFp∗(αF(p))∧dFp∗(βF(p)), which is exactly (F∗α∧F∗β)p.

2.1L1step 1.2∎

The identity and composition laws are inherited from [L1], and step 1.2 gives wedge preservation. Therefore pullback of forms is smooth, functorial, and wedge-preserving.

Depends on

Used by

Dependency tree · two levels

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Sources