Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The canonical map from the integers into Zp is injective and has dense image

Statement

The canonical homomorphism from Z to Zp is injective, and its image is dense in Zp.

Facts & Assumptions

Given: The canonical map from Z to Zp.

[F1]

The canonical map sends m to the residue tuple (mmodpn)n1 (The canonical map from Z to Zp sends an integer to its coherent residue classes modulo p^n).

[L1]

An element of Zp is a compatible system of residue classes modulo pn (The p-adic integers are the compatible residue-class tuples in the inverse limit of Z mod p^n).

Proof

technique · direct
1.1

If an integer m maps to 0, then [F1] says mmodpn=0 for every n1. Thus every power pn divides m, which is possible only for m=0. So the canonical map is injective.

F1givenalgebra
1.2

A basic neighbourhood in Zp fixes some residue class modulo pn. Let x=(xr)Zp and let n1. Choose an integer m representing the coordinate xnZ/pnZ. Then [F1] gives that the image of m has n-th coordinate xn, and [L1] implies that this image agrees with x in every earlier coordinate as well. So every basic neighbourhood of x meets the embedded copy of Z, which is therefore dense.

F1L1givenchoose
2.1

Step 1.1 proves injectivity and step 1.2 proves density. The zero element is treated in both arguments without any extra case split.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources