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The meet of two subobjects is their pullback
Statement
Let and be subobjects of an object in an abelian category, represented by monomorphisms and . Then the meet in the subobject order is represented by the pullback of and .
Facts & Assumptions
Given: Monomorphisms and .
Pullbacks are defined by their commutative square and universal property (Pullbacks and pushouts as limits and colimits of cospans and spans).
A pullback of a monomorphism is a monomorphism (A pullback of a monomorphism is a monomorphism, and a pushout of an epimorphism is an epimorphism).
Subobject inequalities are factorization relations between representatives (Subobjects and quotient objects form oppositely oriented partially ordered collections).
Proof
Form a pullback square tikzcd P \arrow[r, "q"] \arrow[d, "p"'] & C \arrow[d, "c"] \\ B \arrow[r, "b"'] & A. By [L2], the pullback leg is monic, so the composite is monic as well. Because factors through both and , it is a lower bound of the two subobjects.
Let be any lower bound. Then for some and . By the pullback universal property [L1], there is a unique with and . Therefore , so factors through . Hence .
Steps 1.1 and 1.2 show that is a lower bound above every other lower bound. By [L3], the pullback subobject is exactly .
Depends on
Used by
Dependency tree · two levels
10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Daniel Murfet, Abelian Categories, Section 4.2 (standard reference, not scraped)