Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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In a C prime(1/6) group, every nontrivial torsion element is conjugate to a power of a relator root

Statement

Let G=XR be a symmetrised C(1/6) presentation. Every nontrivial torsion element of G is conjugate to a power of a root of some defining relator.

Facts & Assumptions

Given: A nontrivial torsion element gG.

[F2]

Theorem 5.6 of the cited Williams source is the classical torsion theorem for symmetrised C(1/6) presentations: every nontrivial element of finite order is conjugate to a power of a root of some defining relator.

Proof

technique · direct
1.1

Because g is a nontrivial torsion element, the hypotheses of [F2] apply directly. Therefore g is conjugate to a power of a root of some defining relator.

F2given
2.1

Powers are interpreted as in [F1], so step 1.1 is exactly the claimed conclusion.

F1step 1.1

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources