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TPFA discrete Green identity, coercivity, and maximum principle

Statement

Let T be a finite TPFA-admissible cell-face mesh, let every cell be connected through interior faces to a cell with a boundary face, and let TF>0 be the transmissibilities of Orthogonal TPFA diffusion with harmonic face transmissibility. For cell vectors u,v, define (Ahu)K=1∣K∣(∑F=K∣LTF(uK−uL)+∑F⊂∂K∩∂ΩTK,FuK). Then interior fluxes are locally conservative, and for all cell vectors u,v, ∑K∈K∣K∣vK(Ahu)K=∑F=K∣L∈FintTF(vK−vL)(uK−uL)+∑F∈FbdyTK,FvKuK. The stiffness matrix associated with the displayed bilinear identity is symmetric positive definite. Equivalently, Ah is self-adjoint and positive definite in the volume-weighted inner product ⟨u,v⟩h=∑K∣K∣uKvK; its ordinary coordinate matrix need not be symmetric when cell volumes differ. Hence every finite source and boundary-data vector gives a unique solution. If all cell sources and all prescribed boundary face values are nonnegative, then every solution cell value is nonnegative. The maximum-principle claim uses the boundary anchor; no diagonal sign statement alone is used as a substitute for that condition.

Facts & Assumptions

Given: A finite connected cell-face mesh, the positive TPFA transmissibilities, a path from every cell to a boundary face, finite real cell and face vectors, and the cell-balance convention of Orthogonal TPFA diffusion with harmonic face transmissibility.

[F1]

Finite-volume cell-face meshes and geometric regularity: the cell adjacency graph is finite; an interior face belongs to exactly two cells, and a boundary face belongs to one cell.

[F2]

Orthogonal TPFA diffusion with harmonic face transmissibility: TF>0; the two outward fluxes on an interior face are TF(uK−uL) and TF(uL−uK); a homogeneous boundary face contributes TK,FuK to the cell operator.

[A1]

The mesh is boundary anchored: every cell has a finite adjacency path to a cell incident to a Dirichlet boundary face. All cell volumes and transmissibilities are strictly positive.

Proof

1.1F1F2algebra

For an interior face F=K∣L, the shared-flux definitions give QK,F(u)+QL,F(u)=TF(uK−uL)+TF(uL−uK)=0. Thus summing cell balances cancels every interior flux exactly.

1.2F1F2givenalgebra

In ∑K∣K∣vK(Ahu)K, the two terms contributed by an interior face are TF[vK(uK−uL)+vL(uL−uK)]=TF(vK−vL)(uK−uL). A boundary face contributes TK,FvKuK. Summing all faces proves the displayed identity.

2.1A1step 1.2algebra

Set v=u in step 1.2. The resulting stiffness quadratic form is a sum of nonnegative terms. If it is zero, every interior term forces uK=uL, and every boundary term forces uK=0 on its incident cell. The path condition [A1] propagates these zeros through the connected cell graph, so u=0. The finite-dimensional symmetric stiffness matrix therefore has trivial kernel and is positive definite and invertible. Since the volume matrix Mh=diag⁡(∣K∣) is invertible, Ah=Mh−1(MhAh) is also invertible; inhomogeneous boundary values change only the right-hand side.

3.1F1F2A1choosealgebra∎

Suppose u solves the cell balances with fK≥0 and gF≥0. If a cell value has a negative global minimum, choose a minimizing cell K. Every interior summand TF(uK−uL) in its balance is nonpositive, and every boundary summand TK,F(uK−gF) is strictly negative. Since the balance equals ∣K∣fK≥0, all summands must be zero. Thus the minimum propagates unchanged to every adjacent cell along a path from [A1], but at a boundary face the summand TK,F(uK−gF) is strictly negative. This contradiction rules out a negative minimum, so all cell values are nonnegative.

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