Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedverified 2026-09-23 (gpt-6-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Triangular decomposition from a chosen positive root system

Statement

Let Φ+ be a positive system in the root set from Root-space decomposition relative to a Cartan subalgebra and put

n+:=⨁α∈Φ+gα,n−:=⨁α∈Φ+g−α.

Then

g=n−⊕h⊕n+

as a direct sum of vector spaces, n± are Lie subalgebras, and multiplication induces a vector-space isomorphism

U(n−)⊗U(h)⊗U(n+)→∼U(g).

Facts & Assumptions

Given: A Cartan subalgebra h of a complex semisimple Lie algebra g, a supplied root-space decomposition g=h⊕⨁α∈Φgα as in the Statement, and a choice of positive roots Φ+⊆Φ. The assertion is conditional on this decomposition; it does not construct one for an arbitrary Cartan subalgebra.

Proof

technique · direct
1.1given

Group the positive, zero, and negative root spaces in the supplied decomposition. This gives the direct sum g=n−⊕h⊕n+.

1.2givenalgebra

If x∈gα and y∈gβ, Jacobi gives [h, [x,y]]=[ [h,x],y]+[x, [h,y]]=(α+β)(h)[x,y] for every h∈h. Thus [x,y] belongs to the supplied weight space for α+β, and is zero if that nonzero weight is absent. A sum of two positive roots cannot be zero or negative, so n+ is closed under brackets. The same argument applies to n−.

2.1step 1.1step 1.2∎

Choose ordered bases of n−, h, and n+ and concatenate them in that order. The ordered PBW monomials from PBW gives an ordered monomial basis for the enveloping algebra are then exactly products of a monomial in U(n−), one in U(h), and one in U(n+), so multiplication gives the stated vector-space isomorphism.

Depends on

Used by

Dependency tree · two levels

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Sources