Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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The arc length of a unit semicircle is pi

Statement

Every once-traversed semicircle of radius 1 has arc length π. In particular, the upper unit semicircle γ(t)=(cost,sint), 0tπ, has length π.

Facts & Assumptions

Given: The path γ(t)=(cost,sint) on [0,π].

[L2]

The functions sine and cosine are differentiable, with (sint)=cost and (cost)=sint (The derivatives of sine and cosine are cosine and minus sine).

[L3]

For every real t, sin2t+cos2t=1 (Parity and the Pythagorean identity for sine and cosine).

[L6]

Path length is invariant under every continuous surjective monotone reparametrization (Arc length is invariant under every continuous surjective monotone reparametrization, including pauses and reversal).

Proof

technique · direct
1.1

By [L1] and [L2], γ(t)=(sint,cost) on [0,π].

givenL1L2
2.1

By [L3], γ(t)2=sin2t+cos2t=1.

step 1.1L3algebra
3.1

By [L4] and [L5], L(γ)=0π1dt=π.

step 2.1L4L5
4.1

Translating or rotating the displayed path does not change the differences between its points, and reversing or monotonically reparametrizing it does not change its length by [L6]. Thus every once-traversed unit semicircle has length π.

step 3.1L6algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 174 results over 26 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources