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Weighted RatioCut and Ncut spectral relaxations

Statement

Let n≥1, V={1,…,n}, and let W=(wij)∈Rn×n be symmetric, entrywise nonnegative, and zero-diagonal. Put di=∑jwij, D=diag⁡(d1,…,dn), L=D−W, and V+={i:di>0}. If V+≠∅, let D+ and L+ be the principal submatrices indexed by V+ and set Lsym,+=D+−1/2L+D+−1/2. The matrices L and, when defined, Lsym,+ are positive semidefinite. For square B, define tr⁡(B)=∑iBii. For 1≤k≤n, let Rk be the minimum of ∑rcut⁡(Ar,Arc)/∣Ar∣ over partitions of V into k nonempty sets. Then min⁡H∈Rn×k, HTH=Iktr⁡(HTLH)=∑i=1kλi(L), where the eigenvalues, repeated with multiplicity, are ordered increasingly, and a minimizer consists of orthonormal eigenvectors for the k smallest eigenvalues. This relaxed minimum is a lower bound for Rk. When 1≤k≤∣V+∣, let Nk be the minimum of ∑rcut⁡(Ar,Arc)/vol⁡(Ar) over partitions of V+ into k nonempty sets. Then min⁡H∈R∣V+∣×k, HTD+H=Iktr⁡(HTL+H)=∑i=1kλi(Lsym,+), attained at H=D+−1/2Q for bottom-k orthonormal eigenvectors Q of Lsym,+. The corresponding columns u=D+−1/2q satisfy L+u=λD+u, and the relaxed minimum is a lower bound for Nk. These lower bounds make no approximation guarantee for a subsequent rounding. Isolated vertices are excluded from the Ncut objective and may be reported separately as singleton outputs.

Facts & Assumptions

Given: A finite weighted graph with W=WT≥0, zero diagonal, D=diag⁡(di), L=D−W, positive-degree set V+, and an integer k in the admissible range for the partition objective under consideration.

[F1]

Finite weighted graph Laplacian: di=∑jwij, L=D−W, V+={i:di>0}, and Lsym,+=D+−1/2L+D+−1/2 on V+ when it is nonempty.

[F2]

RatioCut and normalized cut for a finite weighted graph: RatioCut partitions all of V and sums cut⁡(Ar,Arc)/∣Ar∣; Ncut partitions only V+ and sums cut⁡(Ar,Arc)/vol⁡(Ar).

[F3]

Quadratic form and kernel of a weighted graph Laplacian: L is positive semidefinite and fTLf=12∑i,jwij(fi−fj)2.

[F4]

RatioCut and Ncut as indicator-matrix traces: RatioCut partitions yield HRTHR=Ik and RatioCut⁡=tr⁡(HRTLHR); positive-volume Ncut partitions yield HNTDHN=Ik and Ncut⁡=tr⁡(HNTLHN).

[F5]

Finite-dimensional trace minimization under orthonormal constraints: for a real symmetric matrix A, the minimum of tr⁡(QTAQ) over QTQ=Ik is the sum of its k smallest eigenvalues, attained by bottom-k orthonormal eigenvectors.

Proof

1.1givenF1F3algebraconstruct

By [F1] and [F3], L is symmetric positive semidefinite. If x∈R∣V+∣, extend it by zero on isolates to x~∈Rn; then xTL+x=x~TLx~≥0, so L+ is positive semidefinite. Since D+−1/2 is a real diagonal matrix, yTLsym,+y=(D+−1/2y)TL+(D+−1/2y)≥0. Thus both Laplacians in the Statement are positive semidefinite.

1.2givenF2F4algebra

For every partition of V into k nonempty sets, [F4] supplies a feasible HR for the real constraint HTH=Ik with trace equal to that partition's RatioCut. The relaxed feasible set therefore contains every discrete indicator matrix, so the infimum over the relaxed feasible set is at most the minimum over the finite nonempty family of partitions.

1.3givenF1F2F4algebra

Let A1,…,Ak partition V+. By [F4], their normalized indicators, restricted to V+, satisfy HTD+H=Ik and have trace objective equal to Ncut. Indeed, if i is isolated then di=0 and ∑jwij=0 with wij≥0 forces every wij=0, so row and column i of L vanish; extending H by zero on isolates leaves the active trace unchanged. Thus the active real feasible set contains every discrete Ncut indicator, and the infimum over the active real feasible set is at most Nk.

2.1givenF1F5step 1.2algebra

The matrix L is real symmetric by [F1]. Applying [F5] with A=L gives min⁡HTH=Iktr⁡(HTLH)=∑i=1kλi(L), attained by orthonormal eigenvectors for the k smallest eigenvalues. Together with step 1.2 this is the claimed RatioCut lower bound.

2.2givenF1F5step 1.3algebraconstruct

The diagonal entries of D+ are strictly positive, so Q=D+1/2H is a bijection from HTD+H=Ik to QTQ=Ik. It also gives tr⁡(HTL+H)=tr⁡(QTD+−1/2L+D+−1/2Q)=tr⁡(QTLsym,+Q). Applying [F5] to Lsym,+ gives the stated Ncut relaxed minimum and optimizer H=D+−1/2Q; with step 1.3 this is the claimed lower bound.

3.1F1step 2.2algebra

If Lsym,+q=λq and u=D+−1/2q, multiplying by D+1/2 gives L+u=λD+u. Conversely, if L+u=λD+u, then q=D+1/2u satisfies Lsym,+q=λq. Thus the symmetric normalized problem is equivalent to the generalized eigenproblem stated.

4.1F1F2step 1.2step 1.3step 2.1step 2.2algebra∎

Every Ncut part is a nonempty subset of V+, so its volume is positive; an isolate has zero volume but is excluded from Nk and can only be reinserted as a separately reported singleton. Steps 1.2, 1.3, 2.1, and 2.2 compare feasible sets and compute the lower bounds; they do not bound the RatioCut or Ncut value after an arbitrary rounding.

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