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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-04
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Zp is Hausdorff, totally disconnected, and complete, and compact assuming Choice

Statement

The space Zp is Hausdorff, totally disconnected, and complete for the p-adic metric. Assuming the Axiom of Choice, it is also compact.

Facts & Assumptions

Given: A Cauchy sequence (x(m))m≥0 in Zp; for the compactness clause, also the Axiom of Choice.

[L1]

An inverse limit of finite discrete groups is Hausdorff, compact, and totally disconnected (Inverse limits of finite discrete groups are Hausdorff and totally disconnected, and compact assuming Choice).

[L2]

The inverse-limit and p-adic metric topologies on Zp agree (The inverse-limit topology on Zp agrees with the p-adic metric topology).

[L3]

Coordinatewise addition and negation make Zp a topological abelian group (Coordinatewise addition and negation make Zp a topological abelian group).

Proof

technique · direct
1.1L1L3givenalgebra

By construction, Zp is an inverse limit of the finite discrete groups Z/pnZ. Therefore [L1] gives that Zp is Hausdorff and totally disconnected, and also compact under the extra Choice hypothesis named in the Statement. The group structure from [L3] is already compatible with this topology.

1.2L2givenchooseconstruct

Fix n≥1. Since the sequence is Cauchy and [L2] identifies the metric balls with the cylinder neighbourhoods, there exists Mn such that for all m,r≥Mn the first n coordinates of x(m) and x(r) agree. Let an be that eventual common n-th coordinate. The compatibility of the x(m) forces the tuple a=(an)n≥1 itself to be compatible, hence an element of Zp.

2.1step 1.2L2algebra

For each n and every m≥Mn, the first n coordinates of x(m) and a agree, so step 1.2 gives dp(x(m),a)≤p−n. Given ε>0, choose n with p−n<ε; then every m≥Mn satisfies dp(x(m),a)<ε. Thus x(m)→a in the p-adic metric. Every Cauchy sequence therefore converges, so Zp is complete.

3.1step 1.1step 2.1∎

Steps 1.1 and 2.1 prove the stated properties.

Depends on

Used by

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