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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The propagated covariance is not the exact covariance of a nonlinear observation map

Statement refuted

Statement refuted: "if U⊆R is open and convex, h:U→R is C2, X:Ω→U is square-integrable with E[X]=μ∈U, and Σ is its covariance matrix, then Cov⁡(h(X))=Dh(μ)ΣDh(μ)T, that is, Var⁡(h(X))=h′(μ)2Var⁡(X)."

This is an unsupported nonlinear extension of The covariance of the linearization is AΣAT, which states the covariance formula for the affine linearization T(X) and does not assert equality with Cov⁡(h(X)).

Facts & Assumptions

Given: The finite weighted set Ω={ω0,ω1,ω2} with w(ω0)=1/2, w(ω1)=w(ω2)=1/4; the random variable Y with Y(ω0)=0, Y(ω1)=1, Y(ω2)=3; and the function h(y)=y3 on the open convex set U=(−1,4).

[L1]

On a finite probability space, expectations are the finite weighted sums of Expectation of a real random variable on a finite probability space, and the finite model determines the probability measure P(A)=∑ω∈Aw(ω) whose integral expectations agree with those sums. (Finite probability spaces, outcome weights, events, and event probabilities, Finite probability spaces are exactly finite full-power-set probability spaces)

[L3]

If h:U→R is C2 on open convex U, ∥Hh(x)∥≤B on U, X takes values in U with E[X]=μ∈U and finite second moment, then the linearization error satisfies ∣E[R]∣≤E∣R∣≤B2E∣X−μ∣2 and E[R2]≤B24E∣X−μ∣4 when the fourth moment is finite. (Mean, mean-square and covariance bounds for second-order linearization error)

Counterexample

1.1givenL1L2algebra

By [L1] the finite weighted set is a probability space and the expectations below are its finite weighted sums: E[Y]=12⋅0+14⋅1+14⋅3=1, E[Y2]=14+94=52, and hence Var⁡(Y)=52−1=32 by [L2].

2.1step 1.1givenL2algebra

The function h(y)=y3 is C2 on U=(−1,4), with h′(y)=3y2, so h′(1)=3 and the propagated variance is h′(1)2Var⁡(Y)=9⋅32=272.

2.2step 1.1givenL1L2algebra

The exact moments of h(Y)=Y3 are E[Y3]=14⋅1+14⋅27=7 and E[Y6]=14⋅1+14⋅729=7304=3652, so Var⁡(h(Y))=3652−72=3652−982=2672.

3.1step 2.1step 2.2algebra

Steps 2.1 and 2.2 give propagated value 272 and exact variance 2672; these are unequal, so the refuted identity fails under the stated hypotheses.

4.1step 1.1step 3.1givenL3algebra

The comparison does not contradict [L3]: on U=(−1,4) the second derivative of h is 6y, of absolute value at most 24, so B=24 is admissible, and the linearization error R=Y3−1−3(Y−1)=Y3−3Y+2 satisfies R=2,0,20 at Y=0,1,3, giving E[R]=6≤242⋅32=18 and E[R2]=102≤2424⋅92=648, both bounds of [L3] holding strictly.

5.1step 3.1step 4.1∎

The hypotheses of the refuted statement hold, the propagated covariance 272 differs from the exact variance 2672, and the remainder bounds of [L3] remain satisfied; hence the propagated covariance controls the actual covariance only through those bounds.

Remarks

This witness is a genuine failure of equality, not of the domination bounds of Mean, mean-square and covariance bounds for second-order linearization error: the bounds hold strictly here. A consumer that reports the propagated covariance as an uncertainty of h(Y) must carry the remainder qualification with it.

Depends on

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