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A congruence whose rest spaces are not tangent to any local hypersurfaces

Statement refuted

Statement refuted: "for every observer congruence on a nonempty open subset of flat Lorentzian four-space, the family of rest spaces is tangent to local hypersurfaces" (Smoothness of the rest-space family and its Frobenius integrability criterion).

Facts & Assumptions

Given: The shearing congruence n=γ(∂0+Ω∂2) on W={∣λx1∣<1/2}⊆R4 with its flat Lorentzian metric g=diag⁡(−1,1,1,1), time orientation N=∂0, and the one-form α=n♭.

[L1]

On W the field n is an observer congruence with Ω=λx1, γ=(1−Ω2)−1/2>0, λ>0, and its rest space at q is nq⊥=ker⁡αq (A shearing observer congruence on flat spacetime: tetrad, adapted chart and non-coordinate frame, Smoothness of the rest-space family and its Frobenius integrability criterion).

[L2]

The rest spaces of a congruence are tangent to local hypersurfaces if and only if α∧dα=0 on the domain, where α=n♭ (Smoothness of the rest-space family and its Frobenius integrability criterion).

[L3]

The flat map is αq(v)=gq(nq,v), so in the chart x the components of α are αa=∑bgabnb (Smoothness of the rest-space family and its Frobenius integrability criterion, A smooth differential k-form).

[L4]

The exterior derivative is R-linear of degree one and satisfies d(β∧γ)=dβ∧γ+(−1)deg⁡ββ∧dγ; the exterior derivative of a smooth function is its differential (The exterior derivative is a graded derivation, The exterior derivative of a function is its differential, The exterior derivative by the invariant vector-field formula).

[L5]

The wedge product of differential forms is defined pointwise by the wedge product of alternating covectors (The wedge product of differential forms).

Counterexample

1.1L1L3algebra

In the chart x the components of n are (γ,0,γΩ,0) and gab=diag⁡(−1,1,1,1)ab, so by [L3] the components of α are α0=−γ, α2=γΩ and α1=α3=0; that is, α=γ(−dx0+Ω dx2), a smooth 1-form on W.

2.1step 1.1L4algebra

Since γ and Ω depend only on x1, their differentials are dγ=γ′ dx1 and dΩ=Ω′ dx1 by [L4], with Ω′=λ and γ′=γ3ΩΩ′. Applying the Leibniz rule of [L4] twice gives dα=dγ∧(−dx0+Ω dx2)+γ d(−dx0+Ω dx2)=γ′ dx1∧(−dx0)+γ′Ω dx1∧dx2+γΩ′ dx1∧dx2=γ′ dx0∧dx1+(γ′Ω+γΩ′) dx1∧dx2.

3.1step 2.1L5algebra

By [L5] and step 2.1, α∧dα=γ(−dx0+Ω dx2)∧[γ′dx0∧dx1+(γ′Ω+γΩ′)dx1∧dx2]. The terms containing a repeated coordinate differential vanish, and using dx2∧dx0∧dx1=dx0∧dx1∧dx2 we get α∧dα=γ[−(γ′Ω+γΩ′)+Ωγ′]dx0∧dx1∧dx2=−γ2Ω′ dx0∧dx1∧dx2=−γ2λ dx0∧dx1∧dx2. Since λ>0 and γ>0 on W, the coefficient −γ2λ is nonzero at every point of W, so α∧dα is nowhere zero on W.

4.1step 3.1L2∎

By [L2], the rest spaces of the congruence are tangent to local hypersurfaces if and only if α∧dα=0; since α∧dα≠0 at every point of W by step 3.1, they are not tangent to any local hypersurface. This refutes the displayed general statement.

Remarks

By the companion example A shearing observer congruence on flat spacetime: tetrad, adapted chart and non-coordinate frame this same congruence does admit an adapted chart, so "existence of an adapted chart" and "integrability of the rest spaces" are genuinely different properties: the first always holds locally, the second fails here. The counterexample makes no claim about congruences with vanishing vorticity, and no global foliation claim.

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