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Kinetic energy depends on the observer even though the invariant mass does not

Statement refuted

The kinetic energy Tn(P)=En(P)−mc2 of a massive particle is a property of the particle alone, independent of the observer n.

Facts & Assumptions

Given: the affine Minkowski model (A,V,η,C+); c>0; m>0; w=(3c/5,0,0); U=γ(c,w) with γ=5/4; P=mU; the observers n1=e0 of the displayed inertial frame and n2=U/c.

[F1]

(Four-momentum and kinetic energy at speed three-fifths c, Example): with w=(3c/5,0,0) and γ=5/4 the four-momentum P=mU has Ee0(P)=5mc2/4, spatial momentum (3mc/4,0,0) and kinetic energy Te0(P)=mc2/4.

[F2]

(A passive boost that brings a moving particle to rest, Example): in the frame obtained by the passive boost with parameter 3/5 along e1 one has E′=mc2, p′=0, the mass shell E′2−c2∣p′∣2=m2c4, and that frame is the particle's rest frame, its four-velocity being c e0′.

[F3]

(Positivity, mass shell and kinetic energy of the observer quantities of a four-momentum, Statement (b)): for P=mU with m>0, U future timelike with η(U,U)=−c2, and n future unit, Tn(P)=mc2(γ−1) with γ=−η(U/c,n)≥1, and Tn(P)=0 if and only if U=cn.

[F4]

(Observer energy, spatial momentum, invariant mass, rest energy and kinetic energy of a four-momentum, Definition): Tn(P)=En(P)−mc2 and En(P)=−c η(P,n); the invariant mass m(P) depends on the scalar η(P,P) alone and hence on no observer.

[F5]

(Four-velocity and four-acceleration of a future timelike worldline, clause (c)): a point observer of the model at an event is a future unit timelike vector n with η(n,n)=−1, and the four-velocity of the observer's own worldline is cn; the four-velocity U of the particle satisfies η(U,U)=−c2 (Norms of four-velocity and four-acceleration, and the observer rest-space decomposition,(a)).

[F6]

(Lorentz forms of inertia (3,1,0) on a 4-dimensional real vector space, Definition): η is bilinear, so η(n2,n2)=c−2η(U,U)=−1 for n2=U/c.

Counterexample

1.1F5F6

Two observers: n1=e0 is future unit by definition of an inertial frame, and n2=U/c satisfies η(n2,n2)=c−2η(U,U)=−1 by [F5] and [F6] and is future timelike; both are point observers of the particle in the sense of [F5], and n1≠n2 because U=γ(c,w)≠c e0 has nonzero spatial part.

1.2F1F3

Kinetic energies: in the frame of n1=e0, [F1] gives Tn1(P)=mc2/4≠0; for n2=U/c one has U=cn2, so [F3] gives γ=−η(n2,n2)=1 and Tn2(P)=mc2(γ−1)=0.

1.3F2F4

Energies and mass: En1(P)=5mc2/4 by [F1] and En2(P)=mc2 by [F2]; the invariant mass is m(P)=m in both cases, depending on the scalar η(P,P) alone by [F4].

2.1step 1.2step 1.3

The same particle and the same vector P therefore have kinetic energy mc2/4 for the observer n1 and kinetic energy 0 for the observer n2, while P and the invariant mass m are unchanged; hence the displayed statement is false: Tn(P) depends on the observer n, and so does En(P) (5mc2/4 versus mc2), whereas the invariant mass does not.

3.1step 1.1step 1.2step 1.3step 2.1∎

The refutation is complete: two future unit observers of the same massive particle give different values of Tn(P) and of En(P), so neither quantity is a property of the particle alone, while the invariant mass m(P)=m is the same in both frames.

Depends on

Dependency tree · 2 levels

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