Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Similar matrices have the same trace

Statement

If square matrices A and B over F are similar, then tr⁡(A)=tr⁡(B).

Facts & Assumptions

Given: Similar matrices A,B∈Mn(F).

[L1]

Similarity means B=P−1AP for an invertible matrix P (Similar matrices: B=P−1AP for an invertible P).

[L2]

For conformable rectangular matrices X,Y, one has tr⁡(XY)=tr⁡(YX) (For A∈Mm×n(F) and B∈Mn×m(F), tr⁡(AB)=tr⁡(BA)).

Proof

technique · direct
1.1givenL1

Choose invertible P with B=P−1AP as in [L1].

2.1step 1.1L1L2

Apply [L2] to X=P−1A and Y=P to obtain tr⁡(B)=tr⁡(P(P−1A)).

3.1step 2.1L1L2L3∎

By associativity and unitality from [L3], P(P−1A)=(PP−1)A=InA=A, so tr⁡(B)=tr⁡(A).

Depends on

Dependency tree · 2 levels

Sources