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DefinitionDefinition: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-11-04 (gpt-6.1-sol)
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Slodowy slice associated to a nilpotent element

Definition

Let f be nilpotent in a finite-dimensional complex simple Lie algebra g, and let (e,h,f) be a chosen sl2-triple. Write ge={x∈g:[e,x]=0}. The Slodowy slice for this chosen triple is the affine subspace Sf=f+ge⊆g. For the fixed nondegenerate invariant form B from def-cft-root-data-for-principal-w-levels, it is identified with B(f,⋅)+B(ge,⋅)⊆g∗. This definition does not assert transversality to adjoint orbits or independence from the chosen triple.

Facts & Assumptions

Given: A nilpotent f, a chosen triple (e,h,f), and the fixed nondegenerate invariant form.

[F1]

Jacobson-Morozov triple for a nilpotent element: every adjoint-nilpotent f in a finite-dimensional complex simple Lie algebra admits a triple (e,h,f) satisfying [h,e]=2e, [h,f]=−2f, and [e,f]=h; the local proof includes the reductive-centralizer induction.

[F2]

Root normalization and dual data for principal W levels and Dual Coxeter number for the normalized invariant form: the fixed normalized invariant form is nondegenerate. The general dual-root realization issue is not used in this form interface.

Proof

1.1givenF1algebra

The map x↦[e,x] is linear, so its kernel ge is a vector subspace. Translating that subspace by f gives a well-defined affine subspace Sf.

2.1F2step 1.1algebra∎

Nondegeneracy of B makes x↦B(x,⋅) an isomorphism g→g∗. It therefore sends the affine subspace f+ge bijectively onto the stated affine subspace of g∗. No orbit-transversality conclusion follows from this definition alone.

Proof status

The affine-slice definition is complete for supplied (e,h,f), and the local Jacobson-Morozov theorem supplies such a triple for every nilpotent f. No transversality or independence from the chosen triple is asserted here.

Depends on

Dependency tree · 2 levels

Sources