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DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Periodic Leray and pressure maps

Definition

Assume Countable Choice and fix d∈{1,2,3}. For a vector Fourier coefficient a(k)∈Cd, define (Pa)(k)=Pka(k) for every k∈Zd, where P0=I and Pk=I−kkT/∣k∣2 for k≠0. For a tensor field F=(Fij)i,j=1d with coefficients in any Hs(Qd), define the scalar pressure map Q by QF^(0)=0 and QF^(k)=−∑i,j=1dkikj∣k∣−2F^ij(k) for k≠0. For q∈Hs(Qd), define ∂jq∈Hs−1(Qd) coefficientwise by ∂jq^(k)=ikjq^(k); for vector fields set ∇q^(k)=ikq^(k), and for tensor fields set div⁡F^i(k)=i∑jkjF^ij(k). These derivative maps are bounded from Hs to Hs−1. The multipliers P and Q are real-preserving and bounded on every Hs, s∈R; P is an orthogonal projection and commutes with these derivatives. For every F and every k∈Zd, their exact identity is the coefficientwise equality ∇QF^(k)=−(I−Pk)div⁡F^(k). In particular, both sides have zero coefficient at k=0.

Facts & Assumptions

Given: The hypotheses and conventions stated in the formulation.

[F1]

Periodic fluid Fourier Sobolev spaces: Fourier coefficients represent the real periodic Sobolev coefficient space, with f^(−k)=f^(k)‾.

[F2]

The Axiom of Countable Choice (ACω): Countable Choice is an explicit assumption of the periodic Fourier coefficient framework.

Proof

Given: d∈{1,2,3}, Countable Choice, and the coefficient spaces in [F1].

1.1givenF1algebra

For k≠0, Pk is real symmetric, Pk2=Pk, and its range is k⊥; P0=I. Thus each multiplier is an orthogonal projection of norm at most one. The scalar multiplier defining Q has absolute value at most ∑i,j∣kikj∣/∣k∣2≤d, so both maps preserve every weighted ℓ2 norm up to a dimension-dependent constant.

2.1givenF1F2step 1.1algebra∎

Since P−k=Pk and the coefficient multiplier for Q is real and even in k, both maps preserve conjugate symmetry and hence real fields. Multipliers commute with ikj, so P commutes with the coefficientwise derivative maps. For k≠0, the ath component of the left side has coefficient −i∑i,j=1dkakikj∣k∣−2F^ij(k), which is the ath component of −(I−Pk)div⁡F^(k) because I−Pk=kkT/∣k∣2. At k=0 both sides vanish by the zero-frequency derivative convention.

Depends on

Dependency tree · 2 levels

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