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Positive transverse photon one-particle space

Definition

Assume Countable Choice The Axiom of Countable Choice (ACω). Let H=L2(R3,d3k;C3),⟨u,v⟩2=∫R3u(k)‾⋅v(k) d3k, with the second-variable-linear convention of Schwartz/distribution spaces and Hilbert Fock conventions; the real momentum dot product and norm are those of The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn. Explicitly extend the real dot product complex-bilinearly to a⋅b=∑j=13ajbj for a,b∈C3. Each complex fiber instead has the positive Hermitian pairing ⟨a,b⟩2=a‾⋅b=∑ja‾jbj and norm ∥a∥2=∑j∣aj∣2; the displayed integral uses this pairing. Hilbert completeness follows from L2 with the integral pairing is a Hilbert space. For k≠0, write n(k)=k/∣k∣ and PT(k)=I3−n(k)n(k)T. Assign any value at k=0, which is a Lebesgue-null set. Let MPT be multiplication by this measurable matrix field and define the positive transverse photon space HT=Ran⁡MPT={u∈H:k⋅u(k)=0 for almost every k≠0}. The inner product on HT is the restriction of that on H. Each nonzero momentum fiber is the two-complex-dimensional plane {a∈C3:k⋅a=0} perpendicular to the real vector k in that Hermitian pairing; no global continuous polarization frame is part of the definition.

Facts & Assumptions

Given: Countable Choice and the L2 Hilbert-space and Fock-pairing conventions stated above.

[A1]

Under Countable Choice, complex L2(μ) with the integral pairing is a Hilbert space. L2 with the integral pairing is a Hilbert space

[A2]
[F1]

The Fock convention uses a second-variable-linear Hilbert pairing. Schwartz/distribution spaces and Hilbert Fock conventions

[F2]

The Euclidean dot product is u⋅v=∑i=13uivi and ∣u∣=u⋅u. The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn

Proof

Given: [A1], [A2], [F1], [F2], and the measurable matrix field in the definition.

1.1F1F2givenalgebra

For each k≠0, nTn=n⋅n=1 by [F2], so PT∗=PT and PT2=(I−nnT)2=I−2nnT+n(nTn)nT=I−nnT=PT. Its complex kernel is span⁡C{n} and its range is the Hermitian perpendicular plane n⊥, of complex dimension two. For z∈C3, put a=nTz. The specified Hermitian pairing and realness of n give ∥PTz∥2=∑j∣zj−nja∣2=∥z∥2−∣a∣2≤∥z∥2. Thus it is contractive, with norm one because it fixes every unit vector in that nonzero perpendicular plane. The arbitrary value at the single point k=0 does not affect its multiplication operator on L2.

2.1A1A2F1F2step 1.1given∎

Under [A2], [A1] makes each complex scalar L2 component complete for its first-variable-linear pairing (u,v)1=∫uv‾. The three-component direct sum is complete componentwise. Its second-variable-linear pairing is ⟨u,v⟩2:=(v,u)1=∫u‾⋅v, with the same norm; [F1] fixes this convention. Thus H is complete. The multiplier MPT is bounded and idempotent by step 1.1. If ur=MPTvr→u in H, then MPTu=lim⁡rMPTur=lim⁡rur=u by boundedness, so u belongs to its range. Thus HT is closed and inherits a positive Hilbert inner product. Since PTu=u is equivalent to n⋅u=0 for unit n by [F2], the pointwise range formula gives the displayed transverse condition almost everywhere.

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