Alphabeta Math
DefinitionDefinition: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Normalized finite Gaussian shell transform

Physical scope

Pure mathematics; no physical premises or physical claim.

Definition

Assume AC and let d≥1. For a real symmetric positive-semidefinite covariance matrix C, write γC=Nd(0,C), allowing singular C. For a nonnegative Borel function f:Rd→[0,∞], define the normalized shell transform TCf(x):=∫Rdf(x+z) dγC(z)∈[0,∞]. This is a Borel function of x. If V:Rd→[0,∞) is finite-valued and Borel, define VC(x):=−log⁡(TC(e−V)(x)). Then VC is a finite nonnegative Borel function, and 0<TC(e−V)(x)≤1 for every x. The covariance convention is E[ZZT]=C. The coordinates x,z use the same finite-regulator field-coordinate convention, so C has the square units of those coordinates. The scalar V(x) is dimensionless in e−V(x); if a physical interpretation identifies V with an action, it is normalized as S/ℏ. The measures γC are normalized probabilities, with no determinant/vacuum factor in TC. The transform is defined at finite regulator only.

Facts & Assumptions

Given: AC, finite d≥1, symmetric positive-semidefinite C, and the functions in the Definition.

[A1]

The Axiom of Choice: the finite-dimensional Gaussian-law definition assumes AC.

[F1]

Multivariate normal law, including singular covariance: for positive-semidefinite C, the Borel probability γC=Nd(0,C) exists, including singular C.

[F2]

Tonelli's theorem for nonnegative measurable functions on a sigma-finite product: for product-measurable nonnegative functions, parameter integrals are measurable and iterated integrals agree.

[F3]

The natural logarithm as the inverse of the exponential function: log⁡ is defined on (0,∞) as the inverse of exp⁡.

[F4]

The exponential function is strictly increasing: exp⁡ is continuous and strictly increasing on R.

Proof

technique · direct measurability and positivity check

Given: The objects and hypotheses in the Definition.

1.1A1F1F2given

Write Bd for the Borel sigma-algebra of Rd and λB for Lebesgue measure restricted to Bd. The countable basis of Euclidean open rectangles gives B(Rd×Rd)=Bd⊗Bd. Hence (x,z)↦f(x+z) is product-measurable because addition is continuous and f is Borel. The measure space (Rd,Bd,λB) is sigma-finite because Rd=⋃n≥1[−n,n]d and each cube has finite measure; (Rd,Bd,γC) is a probability space by [F1]. Applying [F2] to these two spaces makes x↦TCf(x) measurable for Bd, hence Borel, including when the integral is infinite.

2.1F1F2step 1.1algebra

For finite nonnegative Borel V, gx(z):=e−V(x+z) is Borel and satisfies 0<gx(z)≤1. Its integral against the probability γC is at most one. It is strictly positive: if the integral were zero, each set {z:gx(z)≥1/n} would have measure zero, while their countable union is all of Rd, contradicting γC(Rd)=1. Thus TC(e−V)(x)∈(0,1].

3.1F1F3F4step 2.1algebra∎

By [F3], the logarithm is defined at these values. Its continuity follows directly from [F4]: for y0>0 and ϵ>0, strict increase and continuity of exp⁡ give exp⁡(log⁡y0−ϵ)<y0<exp⁡(log⁡y0+ϵ); put δ=min⁡{y0−exp⁡(log⁡y0−ϵ),exp⁡(log⁡y0+ϵ)−y0}>0. If y>0 and ∣y−y0∣<δ, then exp⁡(log⁡y0−ϵ)<y<exp⁡(log⁡y0+ϵ), and strict monotonicity gives ∣log⁡y−log⁡y0∣<ϵ. Hence VC is finite, nonnegative, and Borel. If C=0, then for each coordinate Zi, EZi2=Cii=0. For every n≥1, 0=EZi2≥n−2P(∣Zi∣≥n−1), so Zi=0 almost surely; the finite intersection gives Z=0 almost surely and γ0=δ0; hence T0f=f and V0=V.

Depends on

Dependency tree · 2 levels

Sources