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Tonelli's theorem for nonnegative measurable functions on a sigma-finite product

Statement

Let (X,A,μ) and (Y,B,ν) be sigma-finite measure spaces, and let f:X×Y→[0,∞] be product-measurable. Then x↦∫Yfx dν and y↦∫Xfy dμ are measurable, and

∫X×Yf d(μ×ν)=∫X(∫Yfx dν)dμ=∫Y(∫Xfy dμ)dν.

Facts & Assumptions

Given: Sigma-finite measure spaces (X,A,μ) and (Y,B,ν), and a product-measurable function f:X×Y→[0,∞].

[L1]

Sections of a product-measurable function are measurable. (Every section of a product-measurable function is measurable)

[L2]

For a measurable set E, the indicator function satisfies ∫X×Y1E d(μ×ν)=∫Xν(Ex) dμ=∫Yμ(Ey) dν. (For sigma-finite measures, the two section-measure integrals of a measurable set agree)

[L3]

Every nonnegative measurable function admits an increasing sequence of nonnegative simple functions converging pointwise to it. (Every nonnegative measurable function admits an explicit increasing sequence of simple approximations)

[L4]

Monotone convergence passes increasing limits through the integral. (Monotone convergence for the integral)

[L5]

The nonnegative integral is additive for finite sums of measurable nonnegative functions. (Additivity of the nonnegative Lebesgue integral)

Proof

technique · direct
1.1L2L5

If s is a nonnegative simple function, write s=∑j=1mcj1Ej with cj≥0 and measurable sets Ej. Applying [L2] to each indicator 1Ej and summing by [L5] yields ∫s d(μ×ν)=∫X(∫Ysx dν)dμ=∫Y(∫Xsy dμ)dν. The inner integral functions are measurable because the same is true for each 1Ej and simple combinations preserve measurability.

2.1L1L3L4step 1.1∎

Choose simple functions sn↑f by [L3]. Then for each x and y one has (sn)x↑fx and (sn)y↑fy, so [L4] gives ∫Y(sn)x dν↑∫Yfx dν,∫X(sn)y dμ↑∫Xfy dμ. Applying [L4] once more to the equalities of step 1.1 yields the stated measurability and the equality of all three integrals.

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