Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-29
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FALSE: the rectangle formula determines a unique product measure without any sigma-finiteness hypothesis

Statement

For arbitrary measure spaces, any two measures on AB that agree on every measurable rectangle must agree everywhere.

Facts & Assumptions

Given: Lebesgue measure μ on [0,1], counting measure ν on [0,1], the diagonal D:={(x,y)[0,1]2:x=y}, and the two measures ρ,τ on the same product sigma-algebra supplied by the standard non-sigma-finite Lebesgue/counting construction in the listed Tao source, with ρ(A×B)=μ(A)ν(B)=τ(A×B) on measurable rectangles and ρ(D)=10=τ(D).

[L1]

Under sigma-finiteness, the rectangle formula does determine a unique product measure. (For sigma-finite factors, the product measure exists, has the rectangle formula, is sigma-finite, and is unique)

Refutation

technique · direct
1.1

The witness in the Given line satisfies exactly the hypothesis of the displayed claim: ρ and τ are measures on the same product sigma-algebra and agree on every measurable rectangle.

given
2.1

The same witness also satisfies ρ(D)=10=τ(D), so ρτ. Hence the displayed universal uniqueness claim is false. This shows why the sigma-finiteness hypothesis in [L1] is essential.

L1givenstep 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources