How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
For sigma-finite factors, the product measure exists, has the rectangle formula, is sigma-finite, and is unique
Statement
Let and be sigma-finite measure spaces. Then:
- the set function of The product measure of two sigma-finite measure spaces is a measure on ;
- for measurable rectangles, with the nonnegative extended-product convention ;
- the measure is sigma-finite; and
- it is the unique measure on with the rectangle formula.
Facts & Assumptions
Given: Sigma-finite measure spaces and .
For every product-measurable set , (The product measure of two sigma-finite measure spaces)
Monotone convergence passes increasing limits through nonnegative integrals. (Monotone convergence for the integral)
A measure is determined by its values on a sigma-finite generating pi-system. (Measures agreeing on a generating pi-system are equal under an increasing finite-measure exhaustion from that pi-system)
The nonnegative integral is additive for finite sums of nonnegative measurable functions. (Additivity of the nonnegative Lebesgue integral)
The nonnegative integral agrees with the simple integral, whose zero coefficient on a null cell contributes zero even when another factor is infinite (The nonnegative integral agrees with the simple integral on simple functions, The integral of a nonnegative simple function).
Measurable rectangles form a pi-system that generates .
Since and are sigma-finite, there are measurable exhaustions and with .
Proof
If is a measurable rectangle, then Thus its section-measure function is , where the value outside is zero even when . The simple-function integral [L5] gives with when , and symmetrically when . This proves the rectangle formula in every extended-value case.
Let be pairwise disjoint measurable subsets of , and put . Then is a disjoint union, so for every . The section functions are nonnegative measurable, and finite additivity of their integrals gives Since the section functions for increase pointwise to that of , [L2] gives The empty set has product measure zero, so is a measure.
By [A2] and step 1.1, each rectangle has finite product measure and Hence is sigma-finite.
Let be another measure on with the same rectangle formula. Step 1.1 shows that and agree on the generating pi-system of measurable rectangles, and step 2.1 gives the required sigma-finite exhaustion. Therefore [L3] implies on all of . This proves existence, the rectangle formula, sigma-finiteness, and uniqueness.
Depends on
- The product measure of two sigma-finite measure spaces
- For sigma-finite measures, the two section-measure integrals of a measurable set agree
- Measures on sigma-algebras
- Pi-systems
- Measures agreeing on a generating pi-system are equal under an increasing finite-measure exhaustion from that pi-system
- Finite, sigma-finite, and semifinite measures
- Monotone convergence for the integral
- Additivity of the nonnegative Lebesgue integral
- The nonnegative integral agrees with the simple integral on simple functions
- The integral of a nonnegative simple function
- The product sigma-algebra and its finite iterates
Used by
- Arbitrary products of standard Borel probability spaces Corollary
- A nonmeasurable subset of a null line shows that the product of complete measures need not be complete Counterexample
- Not every compact set is conformally removable Counterexample
- The one-dimensional torus and its normalized Haar integral Definition
- A square-integrable kernel without a continuous representative Example
- Brownian finite-dimensional density Example
- The square of the Volterra operator has zero trace Example
- FALSE: every section of a completed-product measurable function is measurable False statement
- FALSE: the product Lebesgue sigma-algebra is the full Euclidean Lebesgue sigma-algebra False statement
- FALSE: the product of two complete measure spaces is complete False statement
- FALSE: the rectangle formula determines a unique product measure without any sigma-finiteness hypothesis False statement
- Independent-copy symmetrization of random series Lemma
- Product rectangle kernels are dense in product L two Lemma
- The countable-product cylinder premeasure is countably additive Lemma
- Independent random elements have product joint law Theorem
- L two kernels give Hilbert–Schmidt operators Theorem
- On Borel subsets of Rᵐ⁺ⁿ, the product lambdaₘ times lambdaₙ agrees with lambdaₘ₊ₙ Theorem
- The Euclidean Lebesgue measure is the completion of the product of the factor Lebesgue measures Theorem
- The logarithmic unit image is a full lattice Theorem
- Tonelli's theorem for nonnegative measurable functions on a sigma-finite product Theorem
Dependency tree · two levels
34 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Terence Tao, An Introduction to Measure Theory, Proposition 1.7.11 (standard reference, not scraped)
- John K. Hunter, Measure Theory, Theorem 5.14 (standard reference, not scraped)