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One-modulus no-scale cancellation in the stipulated N=1 EFT

Physical scope

Conditional algebraic example in the one-modulus, two-derivative four-dimensional N=1 effective model with constant W and no gauging; no full string background or empirical claim.

Example

Take a single dimensionless chiral coordinate ρ with Im⁡ρ>0, dimensionless Kähler potential K=−3log⁡[−i(ρ−ρˉ)], and dimensionful convention K=MP2K. Let W=W0 be a constant holomorphic superpotential with [W0]=mass3, and include no vector multiplet, gauging, or D-term. Adopt the standard old-minimal auxiliary sector and assume that it generates the entire zero-derivative scalar potential, with no auxiliary-independent contribution. In the stipulated two-derivative four-dimensional N=1 model, the F-term potential vanishes at every point of this patch. Consequently this potential does not fix ρ; the calculation establishes no full Type IIB solution, omitted-mode uplift, or vacuum stability.

Facts & Assumptions

Given: The one-modulus patch Im⁡ρ>0, the coordinate normalization of the GKP modulus interface, MP>0, and the conditional four-dimensional N=1 F-term potential.

[F1]

GKP single overall Kähler-modulus coordinate and normalization gives ρ=b/2+ie4uE, so −i(ρ−ρˉ)=2e4uE>0, and dimensionless K=−3log⁡[−i(ρ−ρˉ)].

[F2]

Four-Dimensional N=1 F- and D-Term Scalar Potential conditionally gives the Einstein-frame F-term potential after eliminating the stated old-minimal auxiliary fields, provided that their sector generates the entire zero-derivative potential and no auxiliary-independent term is added; its current readiness is escalated because of an upstream readiness record, so this example is conditional on that supplier.

[A1]

There is exactly one chiral field, no vector or D-term sector, W=W0 is constant and holomorphic, and K=MP2K with dimensionless ρ. The zero-derivative potential is generated entirely by the old-minimal auxiliary sector of [F2], with no additional auxiliary-independent term.

Verification

1.1givenF1A1algebra

Set X=−i(ρ−ρˉ)=2Im⁡ρ>0. Differentiating K=−3log⁡X gives Kρ=−3/(ρ−ρˉ) and Kρρˉ=−3/(ρ−ρˉ)2=3/X2>0.

2.1givenA1step 1.1algebra

The inverse metric is Kρρˉ=X2/3, and the dimensionless-coordinate covariant derivative is DρW=∂ρW+KρW=KρW0 because ∂ρW0=0. Therefore KρρˉDρWDρW‾=(X2/3)(9/X2)∣W0∣2=3∣W0∣2.

3.1givenF2A1step 2.1algebra

Since Kρρˉ=MP2Kρρˉ, its inverse is MP−2Kρρˉ; inserting step 2.1 into [F2] with the D-term sum empty gives V=eKMP−2(3∣W0∣2−3∣W0∣2)=0 for every ρ in the patch. This is an algebraic deduction inside the stipulated effective model.

4.1givenF1step 3.1algebra∎

The potential is identically constant, so its first and second derivatives vanish everywhere and it supplies no restoring force or mass for ρ. The result is only a no-scale cancellation in the chosen EFT; no full higher-dimensional equations, omitted-field equations, or empirical observations were used.

Depends on

Dependency tree · 2 levels

Sources