Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Finite-depth gravity-wave dispersion — worked interpretation

Example

Take h=1 m, g=94 m s−2, k=1 m−1, and a=110 m. Write xm=x/(1 m), zm=z/(1 m), and ts=t/(1 s) for the numerical coordinate values in SI units. Then s=kh=1, ω=32tanh⁡(1) s−1, and the theorem's mode is

θ=xm−32tanh⁡(1) ts,

η=110 m C(θ),ϕ=320tanh⁡(1) m2 s−1cosh⁡(zm+1)cosh⁡(1)S(θ).

Both comparison frequencies equal ωsh=ωdeep=32 s−1. The exact relative errors are

ωsh2−ω2ωsh2=1−tanh⁡(1),1−ωωsh=1−tanh⁡(1),ωdeep2−ω2ωdeep2=1−tanh⁡(1).

They satisfy 0≤1−tanh⁡(1)≤1/3, 0≤1−tanh⁡(1)≤1/3, and 0≤1−tanh⁡(1)≤2e−2 by the finite-depth theorem. The values are a formal parameter choice, not measured wave data.

Example references

Finite-depth linear mode and quantitative bounds: Finite-depth gravity-wave dispersion with quantitative limits.

Facts & Assumptions

Given: The positive parameter values, dimensional coordinate convention, and linear wave model in the Example.

[F1]

For h,g,k>0, the frequency ω=gktanh⁡(kh) gives the displayed exact linear potential mode and the shallow and deep relative-error bounds (Finite-depth gravity-wave dispersion with quantitative limits).

Verification

1.1givenF1algebra

The assignments give kh=1 and gk=(9/4) s−2, hence ω=(9/4)tanh⁡(1)=(3/2)tanh⁡(1) s−1. The theorem's profile factor is cosh⁡(k(z+h))/cosh⁡(kh)=cosh⁡(zm+1)/cosh⁡(1), and ag/ω=(3/(20tanh⁡(1))) m2 s−1. Thus [F1] specializes to the stated η and ϕ.

2.1givenF1algebra∎

The comparison definitions give ωsh=kgh=(3/2) s−1 and ωdeep=gk=(3/2) s−1. Dividing the dispersion identity ω2=gktanh⁡(1) by either squared comparison frequency yields the exact relative-error expressions in the Example. Applying the bounds in [F1] at kh=1 gives the three stated inequalities, with no decimal approximation or empirical inference.

Depends on

Dependency tree · 2 levels