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Finite-depth gravity-wave dispersion with quantitative limits

Statement

Let h,g,k>0, let a∈R, and set s=kh and ω=gktanh⁡(s), using the positive square root. Here h is depth, g a constant acceleration parameter, and k a positive horizontal wave number; s is dimensionless and a is a real elevation amplitude. The strict positivity of tanh⁡(s) for s>0 makes ω well-defined and positive. Let x,y∈R be horizontal Cartesian coordinates and z∈(−h,0) the vertical coordinate, positive upward with the flat mean surface at z=0 and bottom at z=−h; time t∈R. Write θ=kx−ωt. A surface elevation is the scalar field η(t,x,y), and a velocity potential is a scalar field ϕ(t,x,y,z). Define the finite-depth linear potential-wave problem by

Δϕ=0(−h<z<0),ϕz(t,x,y,−h)=0,

ηt(t,x,y)=ϕz(t,x,y,0),ϕt(t,x,y,0)+gη(t,x,y)=0,

where Δ=∂x2+∂y2+∂z2. Let S,C be the real sine and cosine functions defined on this page. Then

η(t,x,y)=aC(θ),ϕ(t,x,y,z)=agωcosh⁡(k(z+h))cosh⁡(kh)S(θ)

are fields that are C2 in the spatial variables and C1 in time, with the displayed derivatives extending to z=−h and z=0, and they satisfy this system exactly. Define the shallow and deep comparison frequencies by ωsh=kgh and ωdeep=gk. They obey

0≤ωsh2−ω2ωsh2≤(kh)23,0≤1−ωωsh≤(kh)23,0≤ωdeep2−ω2ωdeep2≤2e−2kh.

These are exact statements about the displayed linear boundary problem and its dispersion relation. They assert no nonlinear free-surface solution or error bound.

In the optional SI interpretation, [h]=m, [g]=m s−2, [k]=m−1, [a]=[η]=m, [ω]=s−1, and [ϕ]=m2 s−1.

Facts & Assumptions

Given: The positive constants h,g,k, amplitude a, the fields and equations in the Statement, and s=kh>0.

[A1]

The target equations are the harmonic-potential equation, impermeable bottom condition, and the stated linear kinematic and dynamic surface conditions as defined in the Statement.

[F1]

The scalar Laplacian in Cartesian coordinates is the sum of the pure second partial derivatives (Formal parameterized fluid systems and observables).

[F3]

For real r, cosh⁡r=(er+e−r)/2>0, tanh⁡r=sinh⁡r/cosh⁡r, and sech⁡r=1/cosh⁡r (The six hyperbolic functions and their natural domains).

[F4]

cosh⁡′=sinh⁡, sinh⁡′=cosh⁡, tanh⁡(0)=0, and tanh⁡ is strictly increasing on R (Addition formulas, identities, parity, and derivatives of the hyperbolic functions).

[F7]

For every r≥0, 0≤r−tanh⁡r≤r3/3 and 0≤1−tanh⁡r≤2e−2r (Quantitative shallow and deep bounds for the hyperbolic tangent).

Proof

1.1givenF3F4F5F6algebra

Since s>0, [F4] gives tanh⁡(s)>tanh⁡(0)=0, so [F6] makes ω a positive real number. Set G(z)=cosh⁡(k(z+h))/cosh⁡(kh). By [F3]–[F5], its denominator is positive, G′′(z)=k2G(z), G′(−h)=0, G(0)=1, and G′(0)=ktanh⁡(kh).

1.2givenF7algebra

Since ωsh2=ghk2=gks and ω2=gktanh⁡(s), division by the positive gks gives (ωsh2−ω2)/ωsh2=(s−tanh⁡(s))/s. Applying [F7] and dividing by s>0 proves the first shallow bound.

2.1givenA1F1F2F5step 1.1algebra

The identities in [F2] and the chain rule [F5] imply S′′=−S. The field ϕ is independent of y, and therefore [F1] gives Δϕ=(ag/ω)(G′′−k2G)S(θ)=0. Also ϕz=(ag/ω)G′(z)S(θ), so G′(−h)=0 proves the bottom condition.

2.2givenA1F2F5step 1.1algebra

By [F2] and [F5], ηt=aωS(θ) and ϕt(t,x,y,0)=−agC(θ), using G(0)=1. The surface derivative is ϕz(t,x,y,0)=(agktanh⁡(s)/ω)S(θ)=aωS(θ) because ω2=gktanh⁡(s); also ϕt(t,x,y,0)+gη=−agC(θ)+agC(θ)=0. Thus both surface conditions in [A1] hold.

2.3givenstep 1.1step 1.2algebra

Put r=ω/ωsh>0. step 1.2 gives 0≤1−r2≤s2/3, and 1−r=(1−r2)/(1+r) with 1+r≥1. Hence 0≤1−r≤1−r2≤s2/3, proving the shallow frequency bound.

3.1givenF7algebra∎

Since ωdeep2=gk, the dispersion identity gives (ωdeep2−ω2)/ωdeep2=1−tanh⁡(s). The second inequality of [F7] yields the stated deep bound, with its lower bound as in [F7].

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