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Long-time RWA limitation

Example

Work on C2 with ℏ=1. Keep the original commuting example A=B=σz, ω=1, so H(t)=(1+2cos⁡t)σz and Havg=σz. The exact and averaged propagators from time 0 are

U(t)=e−i(t+2sin⁡t)σz,Uavg(t)=e−itσz.

Their norm difference is 2∣sin⁡(sin⁡t)∣. At tn=π/2+2πn it equals 2∣sin⁡1∣>0 for every n≥0. This proves persistent nondecay of the original commuting error. It alone does not disprove uniform-time smallness as the ratio ∥B∥/∣ω∣ becomes small: in the commuting extension A=σz, B=βσz, β∈R, ω>0, the exact error satisfies

∥U(t)−Uavg(t)∥=2∣sin⁡(βωsin⁡ωt)∣≤2∣β∣ω(t∈R).

To prove the stronger intended general limitation, fix ω>0 and define σ+=(0100), σ−=σ+∗, σx=σ++σ−. For every integer n≥1, let

εn=ω12n+14n2,An=0,Bn=εnσ+,

Hn(t)=eiωtBn+e−iωtBn∗,Havg,n=0.

These are smooth bounded self-adjoint Hamiltonians of precisely the form of Rotating-wave finite-time error. They are noncommuting in time: for suitable t,u, [Hn(t),Hn(u)]=2iεn2sin⁡(ω(t−u))σz≠0. Their oscillatory coefficient norm satisfies ∥Bn∥/ω=εn/ω→0. Nevertheless at the growing times τn=2πn/ω their exact propagator obeys Un(τn)=−I, while Uavg,n(τn)=I. Thus

∥Un(τn)−Uavg,n(τn)∥=2(n≥1).

This is the maximum possible norm distance between unitaries. In particular no general bound sup⁡t≥0∥U(t)−Uavg(t)∥≤f(∥B∥/ω) with f(r)→0 as r→0 can hold for this whole class, even with A=0, fixed positive ω and dimension two. This does not assert that the finite-time theorem's linear growth rate is sharp; it proves the absence of general uniform-time smallness without additional hypotheses. All assertions concern explicit mathematical models, not a laboratory error or measurement.

Verification

Given: the original commuting example, and the circular family Hn with n≥1, ω>0, εn and τn as above.

[F1] The Pauli matrices have σx2=σz2=I and σxσz+σzσx=0, and σzσ+−σ+σz=2σ+; these follow by multiplying their displayed two-by-two matrices, consistent with Finite spin matrices (e).

[F2] Direct differentiation of a displayed unitary solution with initial value I verifies its propagator equation; uniqueness follows from the same D∗D calculation used in the preceding example. No generic ordered Dyson formula, autonomous AC group theorem, or unbounded-domain assertion is needed.

1.1F1F2algebra

The original displayed diagonal exponentials differentiate to iU′=(1+2cos⁡t)σzU, iUavg′=σzUavg, with initial value I. They are therefore the required propagators by [F2]. Left multiplication of their difference by eitσz leaves its norm unchanged and gives diagonal entries e∓2isin⁡t−1, whose common modulus is 2∣sin⁡(sin⁡t)∣. Substitution at π/2+2πn proves the original positive nondecaying subsequence.

1.2F1F2algebra

Define W(t)=exp⁡(iωtσz/2) and Gn=εnσx+(ω/2)σz. The diagonal formula for W gives Wσ+W∗=eiωtσ+ and Wσ−W∗=e−iωtσ−. Hence Hn(t)=εnW(t)σxW(t)∗. Put Vn(t)=W(t)e−itGn. Both factors are unitary, Vn(0)=I, and differentiating gives iVn′=−(ω/2)σzVn+WGne−itGn=εnWσxW∗Vn=HnVn, because W commutes with σz. By [F2], Un=Vn. The sign of W and the positive ωσz/2 term in Gn are essential in this cancellation.

2.1step 1.1algebra

For the commuting extension with real β, integrate its diagonal scalar entries to obtain U(t)=exp⁡[−i(t+2βsin⁡(ωt)/ω)σz]. The same diagonal norm calculation gives 2∣sin⁡((β/ω)sin⁡ωt)∣≤2∣β∣/ω. Thus the original commuting nondecay example admits a time-uniform small-ratio estimate; the stronger failure requires the separate noncommuting construction.

2.2F1step 1.2algebra

By [F1], Gn2=(εn2+ω2/4)I=νn2I, where νn=(ω/2)(1+1/n)>0 from the exact definition of εn. Splitting the absolutely convergent matrix exponential into even and odd powers gives e−itGn=cos⁡(νnt)I−isin⁡(νnt)Gn/νn. At τn=2πn/ω, the angles are ωτn/2=πn and νnτn=π(n+1). Therefore W(τn)=(−1)nI and e−iτnGn=(−1)n+1I, so Un(τn)=−I. Since An=0, Uavg,n(t)=I for every t, and the norm difference at τn is ∥−2I∥=2.

3.1step 2.2algebra∎

The matrix σ+ sends (x,y) to (y,0), so its operator norm is exactly 1; hence ∥Bn∥/ω=1/(2n)+1/(4n2)→0. Also τn→∞ for fixed ω. For noncommutativity, the products σ+σ−=diag⁡(1,0) and σ−σ+=diag⁡(0,1) give [Hn(t),Hn(u)]=εn2(eiω(t−u)−e−iω(t−u))σz=2iεn2sin⁡(ω(t−u))σz. The proposed general function f(r)→0 would give 2≤f(∥Bn∥/ω)→0, a contradiction. This proves the full intended no-general-uniform-smallness conclusion while retaining the distinct commuting nondecay example.

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