Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Constant conformal factor verifies field and volume normalization

Example

Take the theorem's external metric with a constant conformal factor Ω=b>0, so g=b2η. The scalar field is smeared by Φg(f)=Φ0(b3f) relative to dvolg=b4d4x. In particular, Rg=0 and Pg=b−2□η. Relative to dvolg(x)dvolg(y), the two-point kernel is Wg(x,y)=b−2W0(x,y), so its double smearing is b6 times the flat covariance. This example checks the constant-factor normalization only; it asserts no preferred state for a general curved metric.

Facts & Assumptions

Given: ACω, a positive constant b, and the selected massless field construction of Exact massless scalar on a conformally flat external metric.

[A1]

ACω is the countable-choice assumption of The Axiom of Countable Choice (ACω); it is inherited from the conditional QFT and EMG supplier chains.

[F1]

Exact massless scalar on a conformally flat external metric: Rg=−6Ω−3□ηΩ and Pg(Ω−1u)=Ω−3□ηu for smooth u.

[F2]

Exact massless scalar on a conformally flat external metric: for every compact test f, Φg(f)=Φ0(Ω3f).

[F3]

Exact massless scalar on a conformally flat external metric: relative to dvolg(x)dvolg(y), Wg(x,y)=Ω(x)−1Ω(y)−1W0(x,y).

Verification

technique · direct
1.1givenA1F1algebra

Since ∂ab=0, □ηb=0 and [F1] gives Rg=0. Also gab=b−2ηab and dvolg=b4d4x, so the density definition gives □g=b−2□η and hence Pg=b−2□η.

2.1givenA1F2F3step 1.1algebra

Substituting Ω=b into [F2] gives Φg(f)=Φ0(b3f); [F3] gives the relative kernel Wg=b−2W0. In the double smearing the two volume factors contribute b4b4, so the total coefficient is b−2b8=b6, exactly the coefficient from the two test multipliers b3b3.

3.1givenF2F3step 2.1∎

At b=1 these formulas reduce to the flat metric, field, and covariance. Locality is inherited from the theorem and is not checked here; this example checks only the stated normalization and does not assert uniqueness of a vacuum on a nonconstant curved metric.

Depends on

Dependency tree · 2 levels