Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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Formal Dirac spin coefficient in a uniform field

Facts & Assumptions

Given: Use the formal spin term and magnetic-moment convention of Minimal Dirac magnetic square and formal Pauli benchmark. Let m>0 be its mass in kilograms, q=−e with e>0 in coulombs, and define A:R3→R3 by A(x)=12B0e3×x, where B0>0 is in tesla; this is smooth with tesla-metre components and its curl is the constant field B=∇×A:R3→R3, B(x)=B0e3, where e3=(0,0,1). Use χ+=(1,0)T and χ−=(0,1)T in C2, which satisfy σ3χ±=±χ± for the matrix in the supplier.

[F1]

Minimal Dirac magnetic square and formal Pauli benchmark: the formal magnetic term is −(q/m)S⋅B with S=ℏΣ/2 and the minimal coefficient convention has gs=2.

Example

The two spin eigenvalues give opposite formal energy coefficients in the same uniform field. For comparison only, define the formal frequency coefficient νcomp:=eB0/(2πm), whose SI unit is C T kg−1=s−1, equivalently the formal angular-frequency coefficient ωcomp:=2πνcomp=eB0/m. This is a formal comparison only, not a trajectory law or empirical prediction.

Verification

1.1givenF1algebra

With q=−e, the supplier's term is (e/m)S3B0. Since σ3 has eigenvalues ±1, S3 has eigenvalues ±ℏ/2, so the two coefficients are ±eℏB0/(2m)=±μBB0, where μB=eℏ/(2m). Their gap is eℏB0/m.

2.1step 1.1F1algebra∎

Dividing that formal energy gap by ℏ gives the angular-frequency coefficient ωs=eB0/m in rad s−1. The cyclic-frequency coefficient is νs:=ωs/(2π)=eB0/(2πm) in hertz, so νs=νcomp and ωs=ωcomp. This compares formal coefficients only; it is not a full Landau-spectrum result or an empirical prediction.

Depends on

Dependency tree · 2 levels

Sources