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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Two-plaquette SU(2) rectangle

Example

Assume ACω. Take a free-boundary SU(2) square lattice containing a rectangle two plaquettes wide and one plaquette high, and let C follow its oriented face boundary counterclockwise from the lower-left corner. Its loop holonomy UC is the ordered link product, using inverse matrices on reverse edges, and the defining normalized Wilson loop is W(C):=12Tr⁡2(UC). For 0<β≤1, the enclosed area is A=2 plaquettes, so the exact finite-lattice expectation is ⟨W(C)⟩β=λ(β)2=β2/16+O(β4) as β↓0, where

λ(β):=∫SU(2)12Tr⁡2(U)eβTr⁡2(U)/2 dμ2(U)∫SU(2)eβTr⁡2(U)/2 dμ2(U)

is the finite one-plaquette coefficient for μ2, the normalized pushforward of round S3 surface area under the matrix-coordinate map in the finite SU(2) plaquette-measure definition.

Diagram

The black arrows are positively oriented links (east along rows and north along columns). The red arrows trace the counterclockwise boundary C; the top and left portions therefore use inverse link variables. The labels p0,0 and p1,0 are the two plaquettes, and the area count is two. The proof below uses only the ordered products and the theorem, not the diagram.

p0;0p1;0

Facts & Assumptions

Given: The free-boundary SU(2) Wilson model with 0<β≤1 and a rectangle two plaquettes wide and one plaquette high.

[A1]

The proof is carried out over ACω. The Axiom of Countable Choice (ACω)

[F1]

Exact finite-lattice SU(2) Wilson area law in two dimensions: for area A, the normalized fundamental loop expectation is λ(β)A.

[F2]

SU(2) one-plaquette matrix average at strong coupling: λ(β)=β/4+O(β3) as β↓0.

Verification

1.1givenA1F1algebra

The rectangle has A=2⋅1=2 plaquettes, so [F1] gives ⟨W(C)⟩β=λ(β)2. The only inherited choice premise is [A1].

2.1F2step 1.1algebra∎

Write λ(β)=β/4+r(β) with r(β)=O(β3) by [F2]. Then λ2=β2/16+(β/2)r+r2=β2/16+O(β4).

Depends on

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Sources