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Worked length contraction of a rod of rest length 5 at speed 3c/5

Example

In an inertial chart x let the chart x′ be related to x by a boost of speed v=3c/5 along the first spatial axis, γ=5/4, so that x′0=54(x0−35x1) and x′1=54(x1−35x0) (Coordinate formulas of a boost: clock rates, rod lengths, simultaneity and velocity transformation, The passive Lorentz boost with parameter beta). Let L0=5 and let the rod at rest in x′ have endpoints on the worldlines x′1=0 and x′1=5, with vanishing transverse coordinates. Solving the transition for x1 as a function of x0 gives x1=35x0 on the first worldline and x1=35x0+4 on the second, so at every equal x-time the endpoints are separated by 4=L0/γ in the frame x. Explicit witness: the events p:=x−1(5,3,0,0) and r:=x−1(5,7,0,0) are simultaneous in x (both have x0=5) and separated by 4; their x′-coordinates are x′(p)=(4,0,0,0) and x′(r)=(1,5,0,0), so they are not simultaneous in x′ but their x′-separation is 5=L0. Comparing events at equal x′-time instead: the events of the two worldlines with x′0=4 are x−1(5,3,0,0) and x−1(35/4,37/4,0,0), the second of which has x′1=5; at equal x′-time 4 the endpoints are separated by 5, the rest length. Thus the frame x assigns length 4 to a rod of rest length 5 at rest in x′, exactly the contraction L0/γ of clause (ii) of Coordinate formulas of a boost: clock rates, rod lengths, simultaneity and velocity transformation, and the comparison uses the simultaneity slice of the measuring frame in the sense of Simultaneity slices and rest distance relative to a future unit timelike vector.

Facts & Assumptions

Given: Two inertial charts x, x′ of the affine Minkowski model related by the boost of speed v=3c/5 along the first axis with γ=5/4, the number L0=5, the two worldlines x′1=0 and x′1=5 at rest in x′ with zero transverse coordinates, and the witness events p=x−1(5,3,0,0), r=x−1(5,7,0,0) (Inertial frames and inertial charts of the affine Minkowski model, Oriented time-oriented affine Minkowski space (the spacetime primitives)).

[L1]

The transition is x′0=γ(x0−35x1), x′1=γ(x1−35x0), x′2=x2, x′3=x3 with γ=5/4 (Coordinate formulas of a boost: clock rates, rod lengths, simultaneity and velocity transformation, The passive Lorentz boost with parameter beta).

[L2]

Length comparison (clause (ii) of Coordinate formulas of a boost: clock rates, rod lengths, simultaneity and velocity transformation): two worldlines at rest in x′ with x′-separation L0 have x-separation L0/γ at equal x-times, while at equal x′-times their x′-separation is L0.

[L3]

Simultaneity relative to a chart is equality of the chart's time coordinate, and the events simultaneous with p in the frame x are the slice H(p,e0) of the measuring frame (Simultaneity slices and rest distance relative to a future unit timelike vector, Inertial frames and inertial charts of the affine Minkowski model).

Verification

technique · direct
1.1L1L2algebra

On the worldline x′1=ℓ the transition reads γ(x1−35x0)=ℓ, so x1=35x0+ℓ/γ=35x0+45ℓ; for ℓ=0 this is x1=35x0 and for ℓ=L0=5 it is x1=35x0+4. Hence at every fixed x0 the x-separation of the two worldlines is 4=L0/γ as asserted.

1.2L1L3algebra

The witness events: x′(p)=(54(5−35⋅3),54(3−35⋅5),0,0)=(4,0,0,0) and x′(r)=(54(5−35⋅7),54(7−35⋅5),0,0)=(1,5,0,0); the first lies on x′1=0 and the second on x′1=5, both have x0=5 hence are simultaneous in x and separated by 7−3=4; their x′-times 4 and 1 differ, their x′-separation is 5.

1.3L1L2algebra

Equal x′-time comparison: on the second worldline, x′0=54(x0−35(35x0+4))=45x0−3; setting x′0=4 gives x0=35/4 and then x1=35⋅354+4=374, so the two events x−1(5,3,0,0) and x−1(35/4,37/4,0,0) have equal x′-time 4; their x′1-coordinates are 0 and 5, so at equal x′-time the separation is the rest length 5.

2.1step 1.1step 1.2step 1.3∎

Conclusion: the frame x assigns to the rod the length 4 at its own equal-x-time slice, which is exactly L0/γ=5/(5/4)=4 of clause (ii) of [L2]; the same pair of worldlines has x′-separation 5 at equal x′-times, and the witness events show explicitly that the equal-x and the equal-x′ comparisons involve different pairs of events. This verifies the length contraction formula and the role of the measuring frame's simultaneity slice.

Remarks

  • Which events are being compared. The two witness events of step 1.2 are simultaneous in x and not in x′, while the two events of step 1.3 are simultaneous in x′ and not in x; the contracted and the rest lengths therefore refer to different pairs of events on the same two worldlines, which is exactly the content of clause (ii) of Coordinate formulas of a boost: clock rates, rod lengths, simultaneity and velocity transformation.

  • No optical claim. The length 4 assigned by x is the distance of the rod's endpoints on a simultaneity slice of x; it is not an appearance or a photograph, and no light-propagation or measurement model is involved.

Depends on

Dependency tree · 2 levels

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