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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-11-05 (gpt-6.1-sol)
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Static Straight Dirichlet String

Physical scope

One explicit classical solution of the flat tensile bosonic Polyakov model on an open strip with fixed spatial endpoint data; not an empirical observation and not a dynamical D-brane model.

Example

On the strip Σ=R×[0,π], fix a length ℓ>0, choose conformal metric h=diag⁡(−1,+1), and set X0=ℓτ, X1=ℓσ, and Xμ=0 for μ≥2. Fix X1 and all Xμ with μ≥2 at both endpoints by Dirichlet data; X0 satisfies Neumann data. Then X¨−X′′=0, X˙2+X′2=0, X˙⋅X′=0, and γ=diag⁡(−ℓ2,ℓ2), so this is a nondegenerate Lorentzian classical Polyakov/Nambu–Goto solution on the positive branch. The fixed endpoints are prescribed boundary data, not dynamical D-branes.

Facts & Assumptions

Given: ℓ>0; the flat target metric is η=diag⁡(−1,+1,…,+1); τ,σ are dimensionless; h=diag⁡(−1,+1); the stated endpoint variations; and the adopted free Polyakov model.

[F1]

Flat Bosonic String Model defines C2 Polyakov maps on the open strip 0≤σ≤π and the additional nondegenerate Lorentzian immersion branch. Membership in that branch is checked for this example in step 2.2.

[F2]

String Tension Alpha Prime: T=(2πα′)−1>0, and target coordinates have length dimension.

[A1]

Bosonic Polyakov Model: the free tensile flat-target Polyakov action is adopted without endpoint interactions.

[F3]

Polyakov Equations and Virasoro Constraints: a conformal-gauge solution must satisfy X¨−X′′=0, X˙2+X′2=0, and X˙⋅X′=0.

[F4]

Open String Boundary Variation: the strip variation is stationary when each endpoint coordinate is fixed (Dirichlet) or has vanishing normal flux (Neumann).

[F5]

Nambu Goto Polyakov Equivalence: on the positive branch, matched classical Polyakov and Nambu–Goto stationary configurations correspond.

Verification

Given: The fields and data in [A1]–[F5].

1.1givenF1A1algebra

Differentiating the stated map gives X˙=(ℓ,0,…,0) and X′=(0,ℓ,0,…,0). Both second derivatives vanish, so X¨−X′′=0.

2.1F3step 1.1algebra

With the mostly-plus target metric, X˙2=−ℓ2, X′2=ℓ2, and X˙⋅X′=0. Thus both metric constraints in [F3] hold.

2.2givenF1step 1.1algebra

The induced metric has components γ00=−ℓ2, γ01=0, and γ11=ℓ2, so det⁡γ=−ℓ4<0; the map has rank two and lies on γ=ℓ2h, hence λ=ℓ2>0.

2.3givenF4step 1.1

At σ=0,π, X1 and every Xμ with μ≥2 are fixed, so their variations vanish; X′0=0, so the time component has zero Neumann flux. By [F4], the boundary term vanishes with these coordinatewise conditions.

3.1A1F2F5step 1.1step 2.1step 2.2step 2.3∎

Steps 1.1, 2.1, 2.2, and 2.3 verify the Polyakov field equation, both metric constraints, nondegeneracy, and boundary stationarity. Since λ>0, T>0 by [F2], and the same boundary data apply, [F5] gives the classical Nambu–Goto solution as well; no endpoint object is introduced.

Depends on

Dependency tree · 2 levels

Sources