Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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A macrocell count and a nonuniform microscopic distribution

Physical scope

A stipulated two-microstate finite model with a nonuniform probability vector; it is not an equilibrium preparation, measurement or empirical claim.

Example

Let Ω={ω1,ω2} with ω1≠ω2, and declare the finite numerical energy map ϵ:Ω→R by ϵ(ω1)=ϵ(ω2)=0, so the assigned physical energies are E(ωi)=0 J. This supplies the finite microstate pair (Ω,ϵ) required in Macroscopic and microscopic entropy quantities; no mechanical internal-energy or equilibrium-macrostate identification is assumed. Choose M={m} and the constant coarse-graining map π:Ω→M, so both states belong to the macrocell Mm=Ω, and assign p1=1, p2=0. The probability vector is deliberately nonuniform. The example shows that the macrocell-count definition and the Gibbs–Shannon definition can take different values on separately specified inputs.

Facts & Assumptions

Given: The finite model below and the entropy definitions.

[F1]

Macroscopic and microscopic entropy quantities: SB(m)=kBlog⁡Nm, while SG(p)=−kB∑ipilog⁡pi, with the zero-probability summand defined as zero.

[F2]

SI quantities and unit conventions: kB=1.380649×10−23 J K−1>0.

[L1]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: log⁡ is strictly increasing on (0,∞) and log⁡1=0.

[A1]

The two states are distinct, ϵ:Ω→R is identically zero, and π:Ω→{m} is constant. Thus Mm=Ω has Nm=2, and p=(1,0) is a probability vector.

Verification

Given: [F1]–[F2], [L1], and [A1].

1.1F1A1algebra

Since Nm=2, the macrocell entropy is SB(m)=kBlog⁡2.

1.2F1L1A1algebra

The only nonzero probability term is 1log⁡1=0; the p2=0 term is zero by definition. Hence SG(p)=0.

2.1F2L1step 1.1step 1.2algebra∎

Since 2>1, [L1] gives log⁡2>log⁡1=0. With kB>0 from [F2], step 1.1 is strictly positive while step 1.2 is zero, so these two defined quantities differ in this model. This example asserts no general inequality or thermodynamic identification.

Depends on

Dependency tree · 2 levels