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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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Water formation at a boundary of the feasible extent interval

Example

For the reaction 2 H2+O2→2 H2O, let extent ξ and species amounts use moles. The dimensionless stoichiometric column is ν=(−2,−1,2)T in the species order (H2,O2,H2O), and take n0=(2,1,0)T. Then the feasible extent interval is [0,1], and at ξ=0 the tangent cone permits only forward directions h≥0. The matrix of hydrogen and oxygen atom counts annihilates ν. For the explicitly mathematical objective Φ(n)=nH2O, the induced extent function is f(ξ)=2ξ and has a boundary minimum at zero. This is a stoichiometric calculation, not a claim about chemical equilibrium or a measured system.

Facts & Assumptions

Given: The reaction vector, initial amounts, extent convention, and linear objective in the Example.

[L1]

The feasible tangent cone for nonnegative stoichiometric amounts: the feasible tangent cone is determined by nonnegative changes in species whose amounts are zero at the point; the extent derivative is νTμ for a differentiable potential.

Verification

technique · direct calculation
1.1givenalgebra

The species-amount vector is n(ξ)=n0+νξ=(2−2ξ,1−ξ,2ξ)T. Nonnegativity of its third component requires ξ≥0, and nonnegativity of its first two components requires ξ≤1; hence the feasible set is exactly [0,1].

1.2givenalgebra

The elemental count matrix is D=(202021), with first row counting hydrogen atoms and second row oxygen atoms per molecule. Direct multiplication gives Dν=(−4+4,−2+2)T=(0,0)T, so every change n(ξ)−n0=νξ preserves both atom totals.

2.1L1step 1.1algebra

At ξ∗=0, only the water component is zero. Its directional change is (νh)3=2h, so [L1] gives TF(0)={h:2h≥0}=[0,∞). A negative direction is infeasible because it would make the water amount 2ξ negative.

3.1L1step 1.1step 2.1algebra∎

For Φ(n)=n3, the induced function is f(ξ)=Φ(n(ξ))=2ξ. Its derivative at 0 is Df(0)h=2h≥0 for every feasible tangent h≥0, and f(ξ)≥f(0) for every ξ∈[0,1]. This verifies the boundary first-order condition and minimum directly for this chosen mathematical objective.

Depends on

Dependency tree · 2 levels

Sources