Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passverified 2026-11-05 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Current Ward identity for WZW sphere coinvariants

Statement

Let Fz be a linear functional in the dual of the fixed-coordinate coinvariant quotient in def-cft-wzw-sphere-current-coinvariants, with the infinity factor equal to the vacuum. For top vectors vj∈Vλj, x∈g, and each i≤n, Fz(v1⊗⋯⊗x−1vi⊗⋯⊗vn⊗1)=∑j≠iFz(v1⊗⋯⊗x0vj⊗⋯⊗vn⊗1)zi−zj. Here x−1 at the ith slot and x0 at the jth slot are the local affine current modes in the fixed coordinates.

Facts & Assumptions

[A1]

Full AC is assumed in Integrable WZW insertions on a punctured sphere for existence of each supplied insertion module and its top. The identity is conditional on those modules.

Given: Distinct z1,…,zn, top vectors vj, a common level k, and Fz as in the Statement.

[F1]

Fixed-coordinate WZW sphere current coinvariants: a block functional annihilates the summed action of every rational current section.

[F2]

Integrable WZW insertions on a punctured sphere: positive current modes kill each top vector, and the horizontal zero modes give the g-action.

[F3]

Universal affine vacuum module: xm1=0 for m≥0 at infinity.

Proof

1.1A1F1F2F3given

Apply [F1] to the rational current x/(z−zi). At zi, its Laurent expansion is xti−1, whose local action on the slot is x−1. At zj≠zi, its Taylor expansion is xz−zi=∑m≥0(−1)m(zj−zi)−m−1x tjm. The residue-mode convention sends x tjm to xm. On the top vector only the m=0 term survives, by [F2]. At infinity, xz−zi=x t∞1−zit∞=∑m≥0zimx t∞m+1, whose modes all have positive index and kill the vacuum by [F3].

2.1step 1.1algebra∎

The annihilation equation from step 1.1 is the left side of the Statement plus ∑j≠i(zj−zi)−1Fz(…,x0vj,…), equal to zero. Since (zj−zi)−1=−(zi−zj)−1, moving that sum to the other side gives exactly the displayed identity.

Depends on

Dependency tree · 2 levels

Sources