Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Jacobian identity for a specified smooth diffeomorphic flow

Statement

Let n≥1, let I⊆R be an open interval containing 0, and let U⊆Rn be open. Suppose χ:I×U→Rn is jointly C2, each χt(a):=χ(t,a) is a C2 diffeomorphism from U onto an open set Ut, and χ0(a)=a. Let D:={(t,x):t∈I, x∈Ut} be open and let b:D→Rn be C1 with ∂tχ(t,a)=b(t,χ(t,a)). Define F(t,a):=Daχ(t,a), J(t,a):=det⁡F(t,a), and div⁡b:=∑i=1n∂xibi. Then

∂tF=(Dxb)(t,χ)F,∂tJ=J(div⁡b)(t,χ),J(0,a)=1.

In particular J(t,a)>0 for all (t,a)∈I×U, and if div⁡b=0 on D, then J(t,a)=1. The same identities hold on the flat torus Tn:=Rn/Λ, where Λ=Zℓ1+⋯+Zℓn for a linearly independent basis ℓ1,…,ℓn and the smooth structure and Euclidean metric descend from Rn. In that clause, let χ:I×Tn→Tn be jointly C2, with each χt a diffeomorphism and χ0=id⁡. Let π:TTn→Tn be the tangent-bundle projection, and let b:I×Tn→TTn have C1 chart coefficients and satisfy π(b(t,a))=a and ∂tχ(t,a)=b(t,χ(t,a)). In every translation chart write b=∑ibi∂xi and define div⁡b:=∑i∂xibi. Define F(t,a) to be the matrix of Daχt:TaTn→Tχt(a)Tn in the translation frames and J(t,a):=det⁡F(t,a). Translation-chart changes have derivative I, so these matrices, determinants and divergences agree on overlaps. These are identities for supplied flow data; no existence or global-flow theorem is asserted.

Facts & Assumptions

Given: The interval I, open set U, jointly C2 family χ, diffeomorphism and initial-identity hypotheses, and C1 velocity field b in the Statement.

[F1]

Clairaut--Schwarz theorem for continuous second partial derivatives: the two mixed second partial derivatives of a C2 scalar function on an open Euclidean set agree.

[F2]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): for totally differentiable maps, the derivative of a composite is the composite of the derivatives.

[F3]

The derivative of the determinant along an invertible C¹ matrix curve: (det⁡A)′=det⁡A  tr⁡(A−1A′): if A(t) is a differentiable invertible real square-matrix curve, then (det⁡A)′=det⁡A tr⁡(A−1A′).

[F4]

For A∈Mm×n(F) and B∈Mn×m(F), tr⁡(AB)=tr⁡(BA): for matching finite real square matrices, tr⁡(AB)=tr⁡(BA).

[F5]

The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a): a function continuous on a closed interval and differentiable on its interior has an interior point where its derivative equals the interval's average slope.

Proof

1.1givenF1F2algebra

For each component χi, joint C2 regularity and [F1] give ∂t∂ajχi=∂aj∂tχi. Differentiating the given velocity equation in a and applying [F2] yields ∂tF=LF, where L(t,a):=(Dxb)(t,χ(t,a)).

2.1givenF2F3step 1.1

Each F(t,a) is invertible: differentiating χt−1∘χt=id⁡ by [F2] gives Dχt−1(χt(a))F(t,a)=I. Thus [F3] applies to the C1 matrix curve t↦F(t,a) and gives ∂tJ=Jtr⁡(F−1LF).

3.1F4step 1.1step 2.1algebra

By [F4], tr⁡(F−1LF)=tr⁡(FF−1L)=tr⁡L=∑i∂xibi(t,χ(t,a)). Also F(0,a)=I, so J(0,a)=1.

4.1givenF6step 2.1step 3.1

The determinant J(t,a) is continuous and nonzero on I by step 2.1. If it were negative for some t, [F6] on the closed segment with endpoints 0 and t would give a point where J=0, contradicting invertibility. Hence J>0.

4.2givenF5step 3.1algebra

If div⁡b=0, step 3.1 gives ∂tJ=0. For each fixed a, the case t=0 is already J(0,a)=1. For t≠0, apply [F5] to J(⋅,a) on [min⁡(0,t),max⁡(0,t)], whose endpoints are distinct; since its derivative is zero, its endpoint difference is zero, so J(t,a)=J(0,a)=1.

5.1givenstep 1.1step 2.1step 3.1step 4.1step 4.2∎

For the torus clause, fix a∈Tn and t0∈I. By continuity, choose a time neighborhood of t0 on which a and χt(a) stay in translation charts. Their transition maps are translations, so the coordinate matrices of Daχt, their determinants, and the coordinate divergence of b agree on overlaps. In these charts the Euclidean calculations in steps 1.1–3.1 prove both differential identities, and χ0=id⁡ gives J(0,a)=1. Since t0 was arbitrary, the identities hold throughout I; applying steps 4.1 and 4.2 on the closed segment between 0 and any t∈I gives positivity and the divergence-free conclusion.

Remarks

The hypotheses describe an already supplied family of diffeomorphisms and its velocity field. This lemma does not prove that an ODE generates such a family, that a trajectory is global, or that any physical fluid or Hamiltonian model satisfies the hypotheses.

Depends on

Dependency tree · 2 levels

Sources