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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Separability and Hilbert structure of the no-slip dual

Statement

Assume Countable Choice and let V be any separable real Hilbert space. Its continuous real-linear dual V∗, with norm ∥ℓ∥V∗=sup⁡∥v∥V≤1∣ℓ(v)∣, is a separable real Hilbert space. The Riesz map J:V→V∗,Jw(v)=(w,v)V is a surjective linear isometry.

Facts & Assumptions

Given: Countable Choice and a separable real Hilbert space V.

[F1]

V is complete and has a countable dense subset, as specified by the real Hilbert and separability hypotheses in the Statement.

[F2]

The Axiom of Countable Choice (ACω): from each countable sequence of nonempty sets one may select one element; this selects an approximating sequence for the distance minimization below.

Proof

1.1givenF1F2algebra

Let ℓ∈V∗ be nonzero. Its kernel K={v:ℓ(v)=0} is a closed linear subspace. Choose x∉K and put d0=inf⁡k∈K∥x−k∥V. By [F2], choose kn∈K with ∥x−kn∥V→d0. Since (kn+km)/2∈K, the parallelogram identity yields ∥kn−km∥V2=2∥x−kn∥V2+2∥x−km∥V2−4∥x−kn+km2∥V2≤2∥x−kn∥V2+2∥x−km∥V2−4d02, which tends to zero as n,m→∞. Thus (kn) is Cauchy; completeness and closedness give a limit k0∈K attaining the distance. Set y=x−k0≠0; because k0∈K and x∉K, ℓ(y)=ℓ(x)≠0. For any k∈K, the quadratic ∥y−tk∥V2 has its minimum at t=0, so its linear coefficient vanishes and (y,k)V=0.

2.1givenF1step 1.1algebra

For any z∈V, the vector z−ℓ(z)y/ℓ(y) belongs to K. Orthogonality from step 1.1 therefore gives ℓ(z)=ℓ(y)∥y∥V2(y,z)V=(wℓ,z)V,wℓ:=ℓ(y)∥y∥V2y. The zero functional is represented by w0=0. If two vectors represent the same functional, their difference is orthogonal to every vector and hence is zero. Cauchy–Schwarz gives ∥Jw∥V∗≤∥w∥V, while testing at v=w/∥w∥V for w≠0 gives equality. Thus J is a linear isometric bijection.

3.1givenF1step 2.1∎

The image under an isometry of a countable dense subset of V is countable and dense in V∗ because J is onto. The Riesz isometry transports the Hilbert inner product of V to V∗, so the dual is a separable real Hilbert space.

Depends on

Dependency tree · 2 levels

Sources