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Curvature components of the diagonal Bianchi I metric

Statement

For a diagonal Bianchi I datum, write HΣ:=H1+H2+H3=3H. In every local quotient chart, the only nonzero Christoffel symbols are Γ0ii=ai2Hi/c2 and Γi0i=Γii0=Hi. The possibly nonzero lowered curvature components are exactly those obtained from the following values by the displayed sign reversals:

R0i0i=Ri0i0=−ai2(H˙i+Hi2),R0ii0=Ri00i=ai2(H˙i+Hi2),

Rijij=Rjiji=ai2aj2c2HiHj,Rijji=Rjiij=−ai2aj2c2HiHj(1≤i<j≤3).

The Ricci components are

Ric⁡00=−∑i=13(H˙i+Hi2),Ric⁡ii=ai2c2(H˙i+HiHΣ),

and every off-diagonal Ricci component is zero.

Facts & Assumptions

Given: A diagonal Bianchi I datum on a nonempty open interval I⊆R, its positive C2 scale factors and metric, and the inherited ACω context.

[A1]

The quotient and product construction for this datum carries the axiom of countable choice ACω and no stronger choice principle (Diagonal Bianchi I model).

[F1]

In a local quotient chart the metric has entries g00=−c2, gii=ai2, and g0i=0 for i=1,2,3; each ai is positive and C2, and all spatial derivatives of the metric entries vanish (Diagonal Bianchi I model).

[F2]

The connection, curvature, Ricci tensor and their sign/index conventions are given by the coordinate formulas in the local C2 definition (C2 curvature for the diagonal Bianchi I quotient metric).

Proof

technique · direct coordinate calculation
1.1givenA1F1F2algebra

Work under the inherited ACω context [A1]; no choice is used in the following finite coordinate calculation. The inverse metric has g00=−c−2, gii=ai−2 and zero off-diagonal entries by [F1]. Substitution in [F2] gives Γ0ii=12(−c−2)(−2aia˙i)=ai2Hi/c2 and Γi0i=Γii0=12ai−2(2aia˙i)=Hi. Every other coefficient is zero because each differentiated spatial metric entry is zero and the metric matrix is diagonal.

2.1step 1.1F2algebra

The curvature formula [F2] and step 1.1 give R0i0i=(ai2/c2)(H˙i+Hi2) and Ri0i0=−(H˙i+Hi2); lowering the first index gives R0i0i=Ri0i0=−ai2(H˙i+Hi2). Reversing the last two direction indices in the same formula gives R0ii0=Ri00i=+ai2(H˙i+Hi2). For i≠j, its only nonzero product in Rijij is Γii0Γ0jj=aj2HiHj/c2, so Rijij=ai2aj2HiHj/c2; direct substitution with the indices reversed gives Rjiji equal to this and Rijji=Rjiij equal to its negative. Every remaining index pattern contains either a spatial derivative of a metric/connection coefficient or a zero coefficient from step 1.1, so it vanishes.

3.1step 2.1F1F2algebra∎

Contracting the components from step 2.1 with the inverse metric gives Ric⁡00=∑iRi0i0=−∑i(H˙i+Hi2). For each i, Ric⁡ii=g00R0i0i+∑j≠igjjRjiji=ai2c2(H˙i+Hi2)+ai2c2∑j≠iHiHj=ai2c2(H˙i+HiHΣ). The index patterns in step 2.1 give zero for every off-diagonal contraction. These are the displayed Ricci components.

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