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Cosmological dynamics and anisotropic shear

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Diagonal Bianchi I model

Definition

Let c>0 be a fixed conversion constant in metres per second. Let I⊆R be a nonempty open interval of physical time in seconds, and let T2π3=R3/(2πZ)3 have dimensionless angular coordinates x1,x2,x3. Its quotient charts are local lifts to R3; chart changes are translations by elements of (2πZ)3. Give M=I×T2π3 the product smooth structure, so M is a smooth four-manifold without boundary. Here a C2 time-oriented Lorentzian metric datum means a symmetric covariant 2-tensor field g with C2 components in smooth charts, whose value at each point has inertia (3,1,0), together with a smooth vector field N satisfying g(N,N)<0 everywhere. This is the explicit C2 variant of the pointwise signature and time-orientation conditions in Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model; that supplier's metric regularity itself is smooth. Choose positive C2 functions ai:I→(0,∞), i=1,2,3, with values in metres, and set

g=−c2 dt2+∑i=13ai(t)2 (dxi)2,N:=∂t.

In every lifted product chart, g has matrix diag⁡(−c2,a12,a22,a32), so it is symmetric, C2, and has inertia (3,1,0); N is smooth and g(N,N)=−c2<0. Thus (M,g,N) is a C2 time-oriented Lorentzian metric datum in the stated sense. This diagonal, spatially homogeneous metric datum is called a diagonal Bianchi I datum here; homogeneity means its coefficients are independent of the torus coordinates, and no isotropy is required. Define the directional expansion rates, their mean, the spatial volume scale and the squared directional shear by

Hi:=a˙iai,H:=13∑i=13Hi,V:=a1a2a3,σ2:=12∑i=13(Hi−H)2.

Here a˙i=dai/dt; Hi and H have units s−1, V has units m3, and σ2 has units s−2. The symbol σ2 denotes a nonnegative scalar defined by this formula, not a tensor norm on a spacetime frame. This is a geometric ansatz and makes no field-equation or observational claim. The product and quotient constructions carry the inherited axiom of countable choice ACω and use no stronger choice principle.

For comparison with smooth Lorentzian geometry, use the curvature convention R(X,Y)Z=∇X∇YZ−∇Y∇XZ−∇[X,Y]Z and the component order R(∂c,∂d)∂b=Rabcd∂a. The local connection and Ricci components for this C2 metric are defined separately.

DefinitionDefinition: AI-adaptedProof: Not applicableprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

C2 curvature for the diagonal Bianchi I quotient metric

Definition

For a diagonal Bianchi I datum, use local quotient coordinates x0=t,x1,x2,x3, with indices a,b,c,d∈{0,1,2,3}, and let (gab) and (gab) be the displayed metric matrix and its inverse. At this C2 regularity, define

Γabc:=12gad(∂bgdc+∂cgbd−∂dgbc),

Rabcd:=∂cΓadb−∂dΓacb+∑e=03(ΓaceΓedb−ΓadeΓecb),

Ric⁡bd:=∑a=03Rabad,R:=∑b,d=03gbdRic⁡bd,Gab:=Ric⁡ab−12R gab,Gab:=∑c=03gacGcb.

Repeated upper and lower indices in the first two displays are summed over {0,1,2,3}. The first formula gives coefficients symmetric in b,c and, by expansion,

Γdcagdb+Γdcbgad=12(∂cgab+∂agcb−∂bgca)+12(∂cgab+∂bgac−∂agcb)=∂cgab.

Thus these coefficients define a torsion-free, metric-compatible connection in every local quotient chart. It is unique: if Γ′ is another such connection, the lowered difference Cabc:=gad(Γ′dbc−Γdbc) is symmetric in its last two indices by torsion freedom and skew in its first two by metric compatibility. Hence

Cabc=Cacb=−Ccab=−Ccba=Cbca=Cbac=−Cabc,

so C=0. The curvature sign and index order agree with the smooth convention cited in the references below. Since g is C2, the coefficients Γ are C1 and the curvature and Ricci components are continuous. On overlaps, two local lifts differ by a constant translation: the Jacobian is the identity and all second derivatives of the transition map vanish. The metric arrays and their derivatives therefore agree, so the displayed connection and curvature arrays patch consistently over the quotient atlas. This is a local C2 extension for this fixed atlas; no general low-regularity tensoriality theorem is being assumed. It inherits only ACω from the torus and product definitions.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Curvature components of the diagonal Bianchi I metric

Statement

For a diagonal Bianchi I datum, write HΣ:=H1+H2+H3=3H. In every local quotient chart, the only nonzero Christoffel symbols are Γ0ii=ai2Hi/c2 and Γi0i=Γii0=Hi. The possibly nonzero lowered curvature components are exactly those obtained from the following values by the displayed sign reversals:

R0i0i=Ri0i0=−ai2(H˙i+Hi2),R0ii0=Ri00i=ai2(H˙i+Hi2),

Rijij=Rjiji=ai2aj2c2HiHj,Rijji=Rjiij=−ai2aj2c2HiHj(1≤i<j≤3).

The Ricci components are

Ric⁡00=−∑i=13(H˙i+Hi2),Ric⁡ii=ai2c2(H˙i+HiHΣ),

and every off-diagonal Ricci component is zero.

Facts & Assumptions

Given: A diagonal Bianchi I datum on a nonempty open interval I⊆R, its positive C2 scale factors and metric, and the inherited ACω context.

[A1]

The quotient and product construction for this datum carries the axiom of countable choice ACω and no stronger choice principle (Diagonal Bianchi I model).

[F1]

In a local quotient chart the metric has entries g00=−c2, gii=ai2, and g0i=0 for i=1,2,3; each ai is positive and C2, and all spatial derivatives of the metric entries vanish (Diagonal Bianchi I model).

[F2]

The connection, curvature, Ricci tensor and their sign/index conventions are given by the coordinate formulas in the local C2 definition (C2 curvature for the diagonal Bianchi I quotient metric).

Proof

technique · direct coordinate calculation
1.1givenA1F1F2algebra

Work under the inherited ACω context [A1]; no choice is used in the following finite coordinate calculation. The inverse metric has g00=−c−2, gii=ai−2 and zero off-diagonal entries by [F1]. Substitution in [F2] gives Γ0ii=12(−c−2)(−2aia˙i)=ai2Hi/c2 and Γi0i=Γii0=12ai−2(2aia˙i)=Hi. Every other coefficient is zero because each differentiated spatial metric entry is zero and the metric matrix is diagonal.

2.1step 1.1F2algebra

The curvature formula [F2] and step 1.1 give R0i0i=(ai2/c2)(H˙i+Hi2) and Ri0i0=−(H˙i+Hi2); lowering the first index gives R0i0i=Ri0i0=−ai2(H˙i+Hi2). Reversing the last two direction indices in the same formula gives R0ii0=Ri00i=+ai2(H˙i+Hi2). For i≠j, its only nonzero product in Rijij is Γii0Γ0jj=aj2HiHj/c2, so Rijij=ai2aj2HiHj/c2; direct substitution with the indices reversed gives Rjiji equal to this and Rijji=Rjiij equal to its negative. Every remaining index pattern contains either a spatial derivative of a metric/connection coefficient or a zero coefficient from step 1.1, so it vanishes.

3.1step 2.1F1F2algebra∎

Contracting the components from step 2.1 with the inverse metric gives Ric⁡00=∑iRi0i0=−∑i(H˙i+Hi2). For each i, Ric⁡ii=g00R0i0i+∑j≠igjjRjiji=ai2c2(H˙i+Hi2)+ai2c2∑j≠iHiHj=ai2c2(H˙i+HiHΣ). The index patterns in step 2.1 give zero for every off-diagonal contraction. These are the displayed Ricci components.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Kasner vacuum constraints

Statement

Let ai(t)=Ai(t/t0)pi on a nonempty open interval I⊆(0,∞), where Ai>0 are lengths in metres, t0>0 is a time in seconds, and pi∈R are dimensionless exponents. These pi are called Kasner exponents for this power-law branch; define their sums P:=∑i=13pi and Q:=∑i=13pi2. For a nonstatic datum, meaning that not all pi vanish, the geometric vacuum equation Ric⁡=0 in the C2 curvature definition of this page holds exactly when P=Q=1. If all pi=0, then the full curvature tensor vanishes, so the metric is flat in the curvature sense. These are exact statements about the specified finite-dimensional metrics; no singularity or generic cosmological conclusion follows.

Facts & Assumptions

Given: A diagonal Bianchi I datum, the power-law scale factors in the Statement, and the mathematical vacuum condition Ric⁡=0 where invoked. The inherited foundational context assumes ACω only.

[A1]

The Bianchi I product and quotient construction carries ACω and no stronger choice principle (Diagonal Bianchi I model).

[F1]

The scale factors are positive C2 lengths on I⊆(0,∞), and the definitions of Hi, H and V are those of the diagonal Bianchi I datum (Diagonal Bianchi I model).

[F2]

The local Ricci components are Ric⁡00=−∑i(H˙i+Hi2) and Ric⁡ii=ai2(H˙i+HiHΣ)/c2, with zero off-diagonal components; the only potentially nonzero curvature components are the two displayed families (Curvature components of the diagonal Bianchi I metric).

Proof

technique · direct substitution into the local curvature components
1.1givenA1F1F2algebra

Work in the inherited ACω context [A1]; the calculation itself uses only finite sums and differentiation. Put P=∑ipi and Q=∑ipi2. The power laws give Hi=pi/t, H˙i=−pi/t2, and HΣ=P/t, so [F2] yields Ric⁡00=(P−Q)/t2 and Ric⁡ii=ai2pi(P−1)/(c2t2).

2.1step 1.1algebra

Suppose not all pi vanish and Ric⁡=0. Choose an index k with pk≠0. Since ak,c,t are positive, the equation Ric⁡kk=0 from step 1.1 implies P=1. The equation Ric⁡00=0 then implies Q=P=1.

2.2step 1.1F2algebra

Conversely, if P=Q=1, step 1.1 makes every diagonal Ricci component zero, and [F2] makes every off-diagonal component zero; hence Ric⁡=0.

3.1givenF1F2algebra∎

If p1=p2=p3=0, then every Hi and H˙i is zero. Both curvature-component families in [F2] therefore vanish, and every other component is zero by that lemma, so the full curvature tensor vanishes.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Diagonal-source shear equation and isotropic-source decay

Statement

For a diagonal Bianchi I datum, let Λ be a constant in m−2 and let Qi:I→R be continuous functions in m−2. Suppose the spatial diagonal equations

Gii+Λ=Qi(t)(i=1,2,3; no sum over i)

hold, where Gii is defined by the local C2 curvature convention on this page. With Δij:=Hi−Hj and HΣ:=3H, subtracting the equations gives

Δ˙ij+3HΔij=c2(Qi−Qj).

If the diagonal source is isotropic, meaning Q1=Q2=Q3, then VΔij is constant for each pair, and there is a constant C≥0 with units m6s−2 such that σ2=C V−2 throughout I. For unequal diagonal sources the right-hand side remains; this proposition makes no unsourced V−2 claim in that case.

Facts & Assumptions

Given: A diagonal Bianchi I datum on I, its Hi, H, V and σ2, a constant Λ, and the stated spatial diagonal equations with functions Qi.

[A1]

The Bianchi I product and quotient construction carries ACω and no stronger choice principle (Diagonal Bianchi I model).

[A2]

The diagonal equations Gii+Λ=Qi(t) are explicit mathematical hypotheses of this proposition; when Qi≠Qj, their difference is retained as a source term.

[F1]

Hi=a˙i/ai, H=13∑iHi, V=a1a2a3, σ2=12∑i(Hi−H)2, and all ai are positive C2 functions (Diagonal Bianchi I model).

[F2]

The local Einstein components are defined by Gab=Ric⁡ab−12Rgab and the stated raising convention (C2 curvature for the diagonal Bianchi I quotient metric).

[F3]

Ric⁡ii=ai2(H˙i+HiHΣ)/c2 and the off-diagonal Ricci components vanish (Curvature components of the diagonal Bianchi I metric).

[F4]

If a real-valued function is continuous on an interval and differentiable at every interior point with zero derivative there, then it is constant on the interval (A function continuous on an interval I whose derivative vanishes at every interior point of I is constant on I; consequently two such functions with the same derivative differ by a constant).

Proof

technique · subtract the diagonal equations, apply the product rule, and use the zero-derivative constancy result
1.1givenA1A2F2F3algebra

Work under the inherited ACω context [A1]; no choice is used in the component subtraction. Raising the first spatial index in [F3] gives Ric⁡ii=c−2(H˙i+HiHΣ). By [F2], Gii=Ric⁡ii−12R; therefore Gii−Gjj=c−2(H˙i−H˙j+HΣ(Hi−Hj)).

2.1step 1.1A2F1algebra

Subtract the j equation in [A2] from the i equation. The constant Λ and common scalar-curvature term cancel, so step 1.1 gives Δ˙ij+HΣΔij=c2(Qi−Qj). Since HΣ=3H, this is the displayed sourced shear-difference equation. In particular the source vanishes exactly when the two diagonal source functions agree.

3.1step 2.1F1F4algebra

Differentiating V=a1a2a3 gives V˙=V∑ka˙k/ak=VHΣ. Multiplying the equation in step 2.1 by V and applying the product rule yields ddt(VΔij)=c2V(Qi−Qj). Each Hi is C1 because ai is positive and C2, so VΔij is continuous on I and differentiable at every point of I. When the diagonal source is isotropic its derivative vanishes; [F4] then makes VΔij constant on I. For unequal sources the displayed derivative retains the stated forcing term.

4.1step 3.1F1algebra∎

Put di:=Hi−H. Then ∑jΔij=3Hi−HΣ=3di, so Vdi=13∑jVΔij is constant in the isotropic-source case by step 3.1. Consequently V2σ2=12∑i(Vdi)2 is a constant C≥0 with units m6s−2, which is equivalent to σ2=C V−2 because V>0.

5 · Examples, experiments and counterexamples

None yet.

Sources