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Diagonal-source shear equation and isotropic-source decay

Statement

For a diagonal Bianchi I datum, let Λ be a constant in m−2 and let Qi:I→R be continuous functions in m−2. Suppose the spatial diagonal equations

Gii+Λ=Qi(t)(i=1,2,3; no sum over i)

hold, where Gii is defined by the local C2 curvature convention on this page. With Δij:=Hi−Hj and HΣ:=3H, subtracting the equations gives

Δ˙ij+3HΔij=c2(Qi−Qj).

If the diagonal source is isotropic, meaning Q1=Q2=Q3, then VΔij is constant for each pair, and there is a constant C≥0 with units m6s−2 such that σ2=C V−2 throughout I. For unequal diagonal sources the right-hand side remains; this proposition makes no unsourced V−2 claim in that case.

Facts & Assumptions

Given: A diagonal Bianchi I datum on I, its Hi, H, V and σ2, a constant Λ, and the stated spatial diagonal equations with functions Qi.

[A1]

The Bianchi I product and quotient construction carries ACω and no stronger choice principle (Diagonal Bianchi I model).

[A2]

The diagonal equations Gii+Λ=Qi(t) are explicit mathematical hypotheses of this proposition; when Qi≠Qj, their difference is retained as a source term.

[F1]

Hi=a˙i/ai, H=13∑iHi, V=a1a2a3, σ2=12∑i(Hi−H)2, and all ai are positive C2 functions (Diagonal Bianchi I model).

[F2]

The local Einstein components are defined by Gab=Ric⁡ab−12Rgab and the stated raising convention (C2 curvature for the diagonal Bianchi I quotient metric).

[F3]

Ric⁡ii=ai2(H˙i+HiHΣ)/c2 and the off-diagonal Ricci components vanish (Curvature components of the diagonal Bianchi I metric).

[F4]

If a real-valued function is continuous on an interval and differentiable at every interior point with zero derivative there, then it is constant on the interval (A function continuous on an interval I whose derivative vanishes at every interior point of I is constant on I; consequently two such functions with the same derivative differ by a constant).

Proof

technique · subtract the diagonal equations, apply the product rule, and use the zero-derivative constancy result
1.1givenA1A2F2F3algebra

Work under the inherited ACω context [A1]; no choice is used in the component subtraction. Raising the first spatial index in [F3] gives Ric⁡ii=c−2(H˙i+HiHΣ). By [F2], Gii=Ric⁡ii−12R; therefore Gii−Gjj=c−2(H˙i−H˙j+HΣ(Hi−Hj)).

2.1step 1.1A2F1algebra

Subtract the j equation in [A2] from the i equation. The constant Λ and common scalar-curvature term cancel, so step 1.1 gives Δ˙ij+HΣΔij=c2(Qi−Qj). Since HΣ=3H, this is the displayed sourced shear-difference equation. In particular the source vanishes exactly when the two diagonal source functions agree.

3.1step 2.1F1F4algebra

Differentiating V=a1a2a3 gives V˙=V∑ka˙k/ak=VHΣ. Multiplying the equation in step 2.1 by V and applying the product rule yields ddt(VΔij)=c2V(Qi−Qj). Each Hi is C1 because ai is positive and C2, so VΔij is continuous on I and differentiable at every point of I. When the diagonal source is isotropic its derivative vanishes; [F4] then makes VΔij constant on I. For unequal sources the displayed derivative retains the stated forcing term.

4.1step 3.1F1algebra∎

Put di:=Hi−H. Then ∑jΔij=3Hi−HΣ=3di, so Vdi=13∑jVΔij is constant in the isotropic-source case by step 3.1. Consequently V2σ2=12∑i(Vdi)2 is a constant C≥0 with units m6s−2, which is equivalent to σ2=C V−2 because V>0.

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